Let's define some variables. We'll call the length L, and the width W. Then we can express the above algebraically:
300 (perimeter) = 2L + 2W
3600 (area) = L x W
Now let's find one variable in terms of the other:
300 = 2L + 2W
300 - 2W = 2L
(300 - 2W)/2 = L
Since we now have the length in terms of width, we can substitute for L in the second equation:
3600 = L x W
3600 = [(300 - 2W)/2] x W
3600 = (300W - 2W2)/2
7200 = 300W - 2W2
---- That was part one of the solution. Now we have to reformat the equation and use the quadratic formula (for the formula and syntax, visit the Wikianswers link below):
-2W2 + 300W - 7,200 = 0
W = [-300+or-(3002 - 4(-2)(-7,200)1/2]/[2(-2)]
W = [-300+or-(90,000 - 57,600)1/2]/-4
W = [-300+or-(32,400)1/2]/-4
W = (-300 + or - 180)/-4
Quadratic equations usually have two answers, since they are parabolas and will most likely cross the x-axis twice.
The first answer is:
w = (-300 + (-180))/-4
W = -480/-4
W = 120
(L = 30)
Or the second answer:
W = (-300 - (-180))/-4
W = (-120)/-4
W = 30
(L = 120)
Either way, the dimensions of the plot must be 120 ft by 30 ft
Assuming there are two additional width-sized fences to make the division, then 2L + 4W = 1200 ie L + 2W = 600. There are many possible dimensions: L 500, W 50; L 400, W 100 etc etc
12 feet
No, it is not an adverb. A farmer is a noun, a person.
miner The wheat is what the farmer grows to earn money. The diamond is what the miner has to find to earn money.
life+farmer
Assuming there are two additional width-sized fences to make the division, then 2L + 4W = 1200 ie L + 2W = 600. There are many possible dimensions: L 500, W 50; L 400, W 100 etc etc
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A farmer wants to make a square pen to keep some of his animals in a confined area. If one side of the square is 15 feet, how much fencing will he need for the pen?
156 ther
240
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Just over six and three-quarter hours.
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