with the assumptions that the ground is level and the house is vertical this particular triangle has unique properties that will be good to know and remember. 10ft is the length of the hypotenuse, therefore (like on all 30-60-90 triangles) the short side is 1 half of this number 10 ft. or precisely 5 ft from the base of the house, and the long side (side of the house) is 5ft x sq rt of 3 or 8.66 ft. I call this the 1 2 square root of 3 triangle to identify the length of each side given the 60 degree angle. and those numbers (1 2 sq rt of 3) can be multiplied by any known length to determine the other 2. You must know that this is probably the most important trigonometry association to remember. 1 (shortest side), 2 (hypotenuse or the longest side) and sq rt of 3 (long leg) and this is only true with a 30-60-90 triangle
15*cos(60) = 7.5 7.5 m
Its pythagoras: 102 - 52 = vertical height2. So 100-25 = vertical height2. Then the square root of 75 must = vertical height. Which makes the top of the ladder 8.66 feet (8ft 8 inches) from the ground.
Assuming the wall is vertical, the wall, the ground and the ladder form an isosceles right-angled triangle. Pythagoras tells us that the square of the length of the ladder, in this case 225 equals the sum of the squares of the other two lengths, ie the height where the ladder touches the wall and the bottom of the ladder's distance from the wall. As these distances are equal in an isosceles triangle each must be the square root of (225/2) ie sqrt 112.5 which is 10.6066, as near as makes no difference to 10 ft 71/4 inches
5 meters
Providing that the ground is level and that the wall is straight, you have the outline of a right angled triangle with an adjacent angle of 73 degrees and an adjacent length of 1.17 metres. In order to find the length of the hypotenuse (which is the ladder itself) we use the cosine ratio: cosine = adjacent/hypotenuse Which when rearranged is: hypotenuse = adjacent/cosine hypotenuse = 1.17/cosine73 degrees = 4.001755235 So the length of the ladder is 4 metres correct to one significant figure.
90 - 31 = 59 degree
115
Jacob's ladders do not have spreaders to avoid it from twisting when resting against the ship's hull
The ladder forms a right angle with the building: the ground and the building forming the right angle and the ladder forming the hypotenuse. If the length of the ladder is L metres, then sin(49) = 12/L So L = 12/sin(49) = 15.9 = 16 metres.
near the bottom.because the net force is equal to zero
If the angle between the ladder and the ground is 60 deg, and you know the angle between the ground and the wall is 90 deg, then you have a 30-60-90 degree triangle, which is a common triangle. You should memorize this one. The commonest sides of this right triangle are 4-5-6, with the longest side being the hypoteneuse, in this case the ladder leaning from the ground to the wall. The wall is 4m high, the base of the ladder would be 5m out from the wall, and the length of the ladder is 6m.
43 degresses
assuming the wall and ground make a 90 degree angle with one another, Pythagorean's Theorem states the ladder will go 8 feet up the wall.
10 feet, and it is at a very dangerous angle.
9
12
93