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A radius of 1 inch and be 5 inches tall the slant height of the cone is 5.1 inches?
If it is a right cone, then by Pythagoras,
(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2
So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)
If it is a right cone, then by Pythagoras,
(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2
So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)
If it is a right cone, then by Pythagoras,
(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2
So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)
If it is a right cone, then by Pythagoras,
(Slant height)2 = 52 + 11 = 25 + 1 = 26 inches2
So slant height = sqrt(26) inches = 5.099 inches = 5.10 inches (to 2 dp)
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