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Q: A squared plus b squared equals c squared?

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Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.

B squared equals c squared minus a squared then to find B take the square root of you answer for b squared

A squared plus B squared equals C squared. It is the Pythagorean theorem.To do this you would find the two short sides of a right triangle. Then for one short side find the length and multiply it by itself and for the other short side do the same thing. After that add those two up and and find the square root of it. That number you have there is C aka hypotenuse aka the long side. :)

If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2

a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100

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The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.

b = sqrt32 or 4 root 2

pythagoras

C equals the square root of 1000 or 31.622776601683793319988935444327...

Pascal

you use A squared plus B squared equals C squared

no

Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.

The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.

Pythagoras.

you mean c? haha pythagoras

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