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false In order for this to be a right triangle, the sum of the squares of the two shorter sides would have to equal the square of the longest side. 102=100 242= 576 272=729 102+242= 676, which does not equal 272=729, so a triangle with these lengths is not a right triangle.
The length of the longer leg of a right triangle is 3ftmore than three times the length of the shorter leg. The length of the hypotenuse is 4ftmore than three times the length of the shorter leg. Find the side lengths of the triangle.
In a 30-60-90 triangle, the hypotenuse is double the length of the shorter leg.
The short sides of a right triangle are the legs.
There are many lengths that can be used to make triangles. Basically take the longest side, add the two shorter sides together, it can be a triangle as long as the 2 shorter sides added together are longer than the longest side.
For a triangle to exist, the sum of the shorter two sides must be longer than the third side.
No. With the given side lengths the sum of the two shorter sides do not exceed the length of the longest side and would not meet to form a triangle
Yes, the three given lengths will form a triangle. Three lengths can make a triangle if, and only if, the sum of the two shorter lengths is greater than the longest length. The two shorter lengths are 56 ft and 16 ft with a sum of 56 ft + 16 ft = 72 ft 72 ft is greater than 65 ft so 56 ft, 65 ft and 16 ft will make a triangle.
Let the length of the longest side of the triangle be x units.Since the lengths of the sides of the triangle are consecutive even numbers, which differ by 2, the perimeter of the triangle equals to (x - 4) + (x - 2) + x = 3x - 6.Since the length of the longest side is 22 units shorter than the perimeter, the perimeter of the triangle also equals to x + 22. So that3x - 6 = x + 22 (subtract x and add 6 to both sides)3x - x + 6 - 6 = x - x + 6 + 222x = 28 (divide both sides by 2)x = 14Thus the longest side has a length of 14 units.
No. Each side must be shorter than the sum of the other two sides.
The perimeter is the sum of all of the sides of the triangle. If the shorter leg is x, the longer leg is 3x. The hypotenuse is then the square root of x^2 + 3x^2, or 2x. Then the perimeter is x + 3x + 2x, simplified, f(x) = 6x.
The sum of the 2 shorter sides must be greater than the longest side to form a triangle
No. For a right angle triangle, the sum of the squares of the shorter sides equals the square of the longer side (the hypotenuse): 22 + 62 = 40 72 = 49
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false In order for this to be a right triangle, the sum of the squares of the two shorter sides would have to equal the square of the longest side. 102=100 242= 576 272=729 102+242= 676, which does not equal 272=729, so a triangle with these lengths is not a right triangle.
I am not sure what you mean by a "fundamental" number (I've never heard of that term being used with reference to the numbers themselves); I guess you mean an "integer". For a triangle to exist the shorter two sides must be longer than the longest side. Thus there is an upper limit to the length of the longest side of a triangle. For a given perimeter, the longest side must be less than half the perimeter. For a perimeter of 42cm this means that the longest side is less than 42 cm ÷ 2 = 21 cm. If we focus on the longest side of a triangle, as it becomes shorter, one or both of the other two sides must increase in length, they can equal but never be longer than this longest side. Thus there is also a lower limit below which the longest side cannot be; this is when all three sides are equal and the triangle is an equilateral triangle. For a perimeter of 42cm the longest side is greater than or equal to 42 cm ÷ 3 = 14 cm So with a perimeter of 42 cm we have: 14 cm ≤ longest side < 21 cm Which means for an integer length, the longest side can be 14 cm, 15 cm, 16 cm, 17 cm, 18 cm, 19 cm or 20 cm.