Presumably this is a quadratic equation question asking you to find the solution of 2x2+9x-5 = 0 First factorise the expression in the equation in order to find its solution. (2x-1)(x+5) = 0 Solution: x = 1/2 or x = -5
2x2= 4
8x - 9 = 9x - 5 8x - 8x - 9 = 9x - 8x - 5 -9 = x - 5 -9 + 5 = x - 5 + 5 -4 = x
It is: -45x
-9x 2 -12x+5 =
The sum of the given expression would depend on the values of the variables which have not been given.
2x2 + 10 = 9x 2x2 - 9x + 10 = 0 (x - 2)(2x - 5) = 0
2x2 + 10 - 9x = 0 or 2x2 - 9x + 10 = 0 So (x - 2)*(2x - 5) = 0
If: 2x2-9x-5 = 0 Then: (2x+1)(x-5) = 0 Therefore:: x = -1/2 or x = 5
2x2 - 9x + 10 = 2x2 - 4x - 5x + 10 = 2x(x - 2) - 5(x - 2) = (x - 2)(2x - 5)
2x2 + 9x + 10
I suppose you mean, how do you factor it. 7x2 - 9x - 10 = (7x + 5)(x - 2).
x+5+3x-7+9x+3-4x Collect like terms: 9x+1
5*2+9x-2=0 so, going by BODMAS rule 10+9x-2=0 9x=-10+2 9x=-8 x=-8/9 I think!!
minus 4 plus 9 = 5, so 5x
I am trying to read this right: (9 x 5) - x3 = ? or 9 x (5 - x3) = ? Which one is it?
5/x4
Assuming that all the terms are positive it is: 11+11x or 11x+11