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How do you find the midpoint in a given segment?
If the coordinates of the end points are (a,b) and (c,d) then the midpoint is the point whose coordinates are [(a+c)/2, (b+d)/2]
How can you find the slope of a line by only knowing the coordinates?
If you have the coordinates of two points, say P = (a,b) and Q = (c,d), then slope = (b-d)/(a-c) that is, the difference in the y coordinate of the two points divided by the difference in the x coordinate of the points taken in the same order.
How many circle can be drawn passing through two points?
There are infinite circles which can be drawn with 2 defined points.. Because if we have 2 points then we can draw infinite equal intersecting lines in infinite directions, These intersecting lines are the radii of the circles. Like : we have 2 points You can draw infinite isosceles triangles as taking the line joining the points For example (activity) : we have 2 points A, B so let's join A and B which will make line AB and so let's take another point C and place that point in such a way that AC = AB and we observe that there are infinite points which can be placed in such a way like how we marked C. Now draw a circle with center C and radius A, we will observe that the circle also cuts through B and so as we have infinite points like C, so we can have infinite circles ..... And so we conclude that infinite circles with different radii can be drawn through two defined distant points ...
How do you find the function of a curved graph based on a set of points?
Given a set of n points it is possible to find a polynomial of order n-1 to fit them. So if we have 3 points, that means there's a polynomial of order 2 that will pass through all the points. A polynomial of order 2 is also known as a quadratic, or parabola. Let's use an example to illustrate: Take the 3 points (0,0), (1,1), (2,0) Then these will fit a curve with the equation y = ax2+bx+c If we put the first point into this equation (y=0, and x=0), then that means: 0 = 0+0+c so c=0. The second point (y=1, and x=1) shows us that: 1 = a.1+b.1+c = a+b (since c=0). so 1 = a+b. The third point says that: 0 = 4a+2b, so b = -2a. We now have a simultaneous equation in a and b. (1): a+b=1 (2): b=-2a These can easily be solved by substitution giving: a=-1, b=2 Therefore we have the curve y = -x2+2x which fits the three points given above. Technical note: It can be the case that the polynomial required has an order of less than n-1 for n points, but it will never be more.
Associative property addition?
a + (b + c) = (a + b) + c for any [ordinary] numbers a, b, and c.
Is points B and C are collinear?
If points B and C are collinear, it means that they lie on the same straight line. To determine if points B and C are collinear, you would need to know the coordinates or have a visual representation of the points.
What is the working mans definition of A B C are collinear?
The thre points A, B, and C are collinear if they are in the same line.
points A, B, and C are collinear?
fugvniby
Points A B and C are collinear How many lines are determined by A B and C?
# 1
Points A B and C lie along the same line What can these points be called?
Collinear.
What do we call points A B and C are on the same line?
They are collinear points that lie on the same line
Points a b c and d are coplanar b c and d are collinear not a how many lines are determined by a b c and d?
5 its 4
Two points that share the same location of a 2D sketch are said to be A. coincident B. collinear C. concentric D. coplanar?
A. Coincident
What are two or more points called if they lie on the same line?
Points on the same line are collinear (co-linear) points.
Name three collinear points that lie in plane p?
a b c, t r w, z p t; any three variables
How many circles can pass through two given points?
It takes 3 non collinear points to define one specific circle. With only two points an infinite number of circles can be drawn. Proof: Given two points A, B draw the line between them. Then find the perpendicular bisector of the line AB. Any point on the perpendicular bisector is equidistant from the two original points, A and B. A circle with center C and radius AC will then pass through points A and B. There are infinite point C's on the perpendicular bisector so there are infinite circles. Given three points A, B and D you can find the perpendicular bisector for line segements AB and then the perpendicular bisector fof line segment BC. The two perpedicular bisectors will not be parallel because the points A, B and D are non collinear. This means the two perpeniducar bisectors will intercept at only one point C(like any two intercepting lines). This point C is equidistant from points A, B, and D. A circle with center C and radius AC will then pass through all three of the points. Since there is only one point C that lies on both perpendicular bisectors, there is only one circle possible.
How many different lines can be drawn if each line contains at least two of these points a b c d e?
10 lines, but only if no three of them are collinear.
