3 nabh4 + 4 bf3 = 3 nabf4 + 2 b2h6
To determine the mass of HBO2 produced from the combustion of 96.9 g of B2H6, we first need to write the balanced chemical equation for the combustion reaction. The balanced equation is 2 B2H6 + 9 O2 → 4 B2O3 + 6 H2O. From this, we can see that 2 moles of B2H6 produce 4 moles of HBO2. First, calculate the molar mass of B2H6 (27.67 g/mol) and convert 96.9 g into moles: 96.9 g B2H6 * (1 mol/27.67 g) ≈ 3.49 mol B2H6. Using the stoichiometry from the reaction, 3.49 mol of B2H6 will produce 6.98 mol of HBO2. The molar mass of HBO2 is approximately 33.81 g/mol, so the total mass of HBO2 produced is: 6.98 mol * 33.81 g/mol ≈ 236.4 g. Thus, approximately 236.4 g of HBO2 is produced.
This chemica equation is:B2H6 + 3 O2 = B2O3 + 3 H2O
In the given reaction, B2H6 reacts with 3 O2 to form B2O3 and 3 H2O. To balance the reaction, 12 electrons are transferred: 12 electrons are lost by the boron atoms in B2H6, and 12 electrons are gained by the oxygen atoms in O2 to form water molecules.
B2h6
Boron hexahydride
Diborane is the name for B2H6.
B2H6 is a covalent molecule. It consists of covalent bonds between boron and hydrogen atoms, sharing electrons to form the molecule.
The oxidation number for boron in B2H6 is +3, and the oxidation number for hydrogen is -1. Each boron atom has an oxidation number of +3, and each hydrogen atom has an oxidation number of -1 in the B2H6 molecule.
C2H4Br2 is the molecular formula for dibromoethane, it is also known as ethylene bromide.
because ch4 has an octett and bh3 not so it dimerises to b2h6
B2Cl6 is the formula of diboron hexachloride.'Di' = 2 and 'Hexa' = 6However:I could only find BCl3 (boron trichloride) or B2H6 (diborane) in my chemical text books, and one reaction with both of the last examples:4 BCl3 + 3 LiAlH4 → 2 B2H6 + 3 LiAlCl4but no confirmation of B2Cl6 molecules. So I doubt if it exists.
Yes, boron is commonly combined with other elements. For example, boron and hydrogen form diborane, B2H6