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Suppose the interior angle is x degrees.

Then the exterior angle is 180 - x degrees.

x = 5*(180-x) = 900 - 5x

So 6x = 900 so that x = 150 degrees.

So exterior angle = 30 degrees.

If the polygon has n sides (and n angles) the sum of its exterior angles is 30*n

But the exterior angles of a polygon add to 360 degrees

So 30*n = 360 so that n = 12.

ANSWER: 12 sides.

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Q: Calculate number of sides of a regular polygon has if an interior angle is five times the size of an exterior angle?
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