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Use the Equation, Resolving Power=lambda/2(Numerical Aperture). So, given the values for Numerical Aperture(NA): If NA=0, then R=0, NA=0.2, then R=1500, NA=0.4, then R=750, etc. Simply solve the equation substituting the provided Numerical Aperture (NA) values in.

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Q: Calculate the resolving power if the wavelength is 600 nm and the numerical apertures are 0 0.2 0.4 0.6 0.8 and 1.0?
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What do you mean by resolving power of telescope?

The "resolving power" of a telescope is a measure of the ability of a telescope to distinguish between two separate objects that appear to be very close together in the sky.


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What does the term resolving power refer to?

The question is about the resolving power of optical instruments like telescope and microscope.It is the ability of the instrument to resolve the images of two points that are close to each other. If dθ is the angular separation, resolving power is given by the formulaR = 1/dθ = D/1.22 λ where Dis the aperture of the objective; λ is the wavelength of the light .


How can you enhance the resolving power of microscope?

By using immersion oil


What limits the resolving power of an electron microscope?

Since there might be problems with the specimen preparation.


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The limit of resolving power of a microscope is described by the Abbe criterion: d=wl/NA d being the minimal resolvable distance between two spots of the object wl being the wavelength of the light used NA being the numerical aperture of the microscope, which is equal to n*sin(a) with n being the refraction index of the immersion liquid between object and objective a being the aperture angle because sin(a) is always smaller than 1 and n cannot rise above 1.7, the maximal resolving power of a microscope is about d=wl/2 and thus only depends on the wavelength of the light used, which normally will be about 600 nm.


What happens to contrast and resolving power when the aperture of the condenser of a compound microscope is decreased?

That will depend whether the microscope is designed to cope with the new wavelength as well as it did with the old. For example, ordinary visible-light microscopes are useless for ultraviolet. The absolute limit to resolving power with perfect optics is about quarter of a wavelength but real microscopes fall short of this.


What is a electron micrscope?

Instead light electron beam is used. Wave nature of matter is being used in this device. Resolving power depends inversely on the wavelength of the light or radiation being used. So to improve the resolving power some 2000 times we have to use electron beam whose de Broglie wavelength is of the order 10-10 m


Why is resolving power important in microscopy?

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What does resolving power of a microscope depend on?

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