Use the Equation, Resolving Power=lambda/2(Numerical Aperture). So, given the values for Numerical Aperture(NA): If NA=0, then R=0, NA=0.2, then R=1500, NA=0.4, then R=750, etc. Simply solve the equation substituting the provided Numerical Aperture (NA) values in.
The "resolving power" of a telescope is a measure of the ability of a telescope to distinguish between two separate objects that appear to be very close together in the sky.
Resolving power = 0.5x wavelength/ numerical aperture (n sin theta)n sin theta in most microscope have value = 1.2 and 1.4therefore:R. P. = 0.5x500nm/ 1.25 = 200nm = 0.2 microns.(conv. 1000nm = 1micron).
Resolving power of microscope is inversely related to the wavelength of the light used. So shorter the wavelength, greater the resolving power.
The ability of an optical instrument expressed in numerical measure to resolve the image of two nearby points is termed as resolving power. The dispersive power of a diffraction grating is defined as the rate of change of the angle of diffraction with the wavelength of lite. S M SOHEL RANA IU
The question is about the resolving power of optical instruments like telescope and microscope.It is the ability of the instrument to resolve the images of two points that are close to each other. If dθ is the angular separation, resolving power is given by the formulaR = 1/dθ = D/1.22 λ where Dis the aperture of the objective; λ is the wavelength of the light .
By using immersion oil
Since there might be problems with the specimen preparation.
The limit of resolving power of a microscope is described by the Abbe criterion: d=wl/NA d being the minimal resolvable distance between two spots of the object wl being the wavelength of the light used NA being the numerical aperture of the microscope, which is equal to n*sin(a) with n being the refraction index of the immersion liquid between object and objective a being the aperture angle because sin(a) is always smaller than 1 and n cannot rise above 1.7, the maximal resolving power of a microscope is about d=wl/2 and thus only depends on the wavelength of the light used, which normally will be about 600 nm.
That will depend whether the microscope is designed to cope with the new wavelength as well as it did with the old. For example, ordinary visible-light microscopes are useless for ultraviolet. The absolute limit to resolving power with perfect optics is about quarter of a wavelength but real microscopes fall short of this.
Instead light electron beam is used. Wave nature of matter is being used in this device. Resolving power depends inversely on the wavelength of the light or radiation being used. So to improve the resolving power some 2000 times we have to use electron beam whose de Broglie wavelength is of the order 10-10 m
resolving power is the ability of an imaging device to separate distinctive points of an object; it is important because the more resolving power a microscope has the better we can see the cell and its structures
In a light microscope the resolution of the image it can project is limited by the distance each photon travels in its wavelength. Beneath this minimum distance, the "noise" of the photon's movement along its path overwhelms any resolution the light source may otherwise provide.