Area = 0.5*base*height Note that the given dimensions would not form a triangle
A right triangle has a hypotenuse of 12cm and a leg that is 9cm the other leg would be 7.94. This is a math problem.
This is not an equilateral triangle.
Area 51.
Use Pythagoras' theorum a2 = b2 + c2 a2 = (9x9) + (12x12) 225 = 81 + 144 Ö225 = 15cm > 14cm. answer NO.
Perimeter = 6cm + 6cm + 9cm + 9cm = 30cm
27cm squared
No
12 cm
A right triangle cannot have those lengths, so no.It would be a scalene triangle (no sides are the same)
The surface area of a cylinder with a radius of 6cm and a height of 9cm is 565.5 units2
Area = 0.5*base*height Note that the given dimensions would not form a triangle
If you are talking about 9cm, 9cm and 1cm then yes it can form a triangle because this would be an isosceles triangle. The two longer sides add up to longer than the short side so it can be a triangle.
It would help to answer the question if there was any information about the shape itself: a triangle, a parallelogram, ... Clearly, that was too much to expect.
The area of rectangle is : 18.0
Area = 6*9 = 54 square cm
12 Pythagorean theorem