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Can anyone solve x plus 2y equals 8 and 3x-2y equals 8 as a simultaneous equation and show their working?
S3anst3r2010
x+2y=8 Here you must add the expressions (2y - 2y = 0)
3x-2y=8
4x=16 Now you are left with a multiple of x so you can simply divide by 4
x=4 on both sides of the =
4+2y=8 Now you substitute x=4 into one of the original equations to find y
2y=4
y=2
Hope this helped.
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