You can solve lineaar quadratic systems by either the elimination or the substitution methods. You can also solve them using the comparison method. Which method works best depends on which method the person solving them is comfortable with.
Simultaneous equations can be solved using the elimination method.
Algebraic expressions can't be solved because they are not equations but they can be simplified.
A quadratic equation can be solved by completing the square which gives more information about the properties of the parabola than with the quadratic equation formula.
If you mean 3x2+4x-2 = 0 then it can be solved by means of the quadratic equation formulla
X = 135 and y = 15 Solved by addition and substitution
By elimination or substitution
For systems with more than three equations, Gaussian elimination is far more efficient. By using Gaussian elimination we bring the augmented matrix into row-echelon form without continuing all the way to the reduced row-echelon form. When this is done, the corresponding system can be solved by the back-substitution technique.
The discriminant
The quadratic formula is used to solve the quadratic equation. Many equations in which the variable is squared can be written as a quadratic equation, and then solved with the quadratic formula.
A quadratic equation normally has 2 solutions and can be solved by using the quadratic equation formula.
Both the substitution method and the linear combinations method (or elimination method) are techniques used to solve systems of linear equations. In the substitution method, one equation is solved for one variable, which is then substituted into the other equation. In contrast, the linear combinations method involves adding or subtracting equations to eliminate one variable, allowing for the direct solution of the remaining variable. While both methods aim to find the same solution, they differ in their approach to manipulating the equations.
Simultaneous equations can be solved using the elimination method.
Algebraic expressions can't be solved because they are not equations but they can be simplified.
All quadratic equations can be solved using the quadratic formula, which is applicable to any equation in the standard form ( ax^2 + bx + c = 0 ), where ( a \neq 0 ). However, if the equation does not fit this standard form—such as if it is not a polynomial, if it contains non-numeric coefficients, or if it is missing the ( x^2 ) term (making it linear instead)—then it cannot be solved using the quadratic formula.
If you mean: x = 8y+5 and 3x-2y = 11 then the simultaneous equations can be solved by a process of elimination. -------------------- Since the first equation is solved for x, substitution should be easy. There is no "right" answer to this question - it depends on your taste and experience.
When an equation cannot be solved for "x" to find the zeroes, the quadratic formula can be used instead for the same purpose.
Yes, however not all quadratic equations can easily be solved by factoring, sometimes you can factor and sometimes it is easier to use the quadratic formula. Example: x2 + 4x + 4 This can be easily factored to (x + 2)(x +2) Therefore the answer is -2 by setting x +2 = 0 and solving for x This can be done using the quadratic equation and you would get the same results, however, it was much faster to factor instead.