Simultaneous equations can be solved using the elimination method.
Algebraic expressions can't be solved because they are not equations but they can be simplified.
A quadratic equation can be solved by completing the square which gives more information about the properties of the parabola than with the quadratic equation formula.
If you mean 3x2+4x-2 = 0 then it can be solved by means of the quadratic equation formulla
X = 135 and y = 15 Solved by addition and substitution
By elimination or substitution
For systems with more than three equations, Gaussian elimination is far more efficient. By using Gaussian elimination we bring the augmented matrix into row-echelon form without continuing all the way to the reduced row-echelon form. When this is done, the corresponding system can be solved by the back-substitution technique.
The discriminant
The quadratic formula is used to solve the quadratic equation. Many equations in which the variable is squared can be written as a quadratic equation, and then solved with the quadratic formula.
A quadratic equation normally has 2 solutions and can be solved by using the quadratic equation formula.
Simultaneous equations can be solved using the elimination method.
Algebraic expressions can't be solved because they are not equations but they can be simplified.
If you mean: x = 8y+5 and 3x-2y = 11 then the simultaneous equations can be solved by a process of elimination. -------------------- Since the first equation is solved for x, substitution should be easy. There is no "right" answer to this question - it depends on your taste and experience.
When an equation cannot be solved for "x" to find the zeroes, the quadratic formula can be used instead for the same purpose.
Yes, however not all quadratic equations can easily be solved by factoring, sometimes you can factor and sometimes it is easier to use the quadratic formula. Example: x2 + 4x + 4 This can be easily factored to (x + 2)(x +2) Therefore the answer is -2 by setting x +2 = 0 and solving for x This can be done using the quadratic equation and you would get the same results, however, it was much faster to factor instead.
It is a quadratic equation and when solved it has equal roots of 3/2 or 1.5
It comes from completing the square of a general quadratic. Many people believe Brahmagupta first solved this in 628 AD.