sqrt(a)+sqrt(b) is different from sqrt(a+b) unless a=0 and/or b=0.
*sqrt=square root of
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
The square root of 2 is an irrational number because it cannot be expressed as a ratio or fraction, a/b, where a and b are whole-number integers, and b does not equal zero. this is true but in simpler terms, it's b/c it's and on-going # just like pi (3.14.... and so on) and it goes on forever so there is no square root, so it is irrational.
b over the square root of 5 The square root of 5b squared is 5b, and the simplified form of the square root of 125 is 5 root 5. The 5s then cancel out leaving b over the square root of 5.
Unfortunately the first term to be squared is not given. However, if the question was about a2 + b2, I regret that there is no simplification. You simply have to calculate the two squares, add them and take the square root.
it's the bit in the square root sqrt of (b squared minus 4ac) when a,b and c are the values belonging to the equation ax(sqared) plus bx plus c
The square root of a/b is equal to the square root of a divided by the square root of b. I hope this helps you.
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
Yes, the answer is the square root of 2b.
It's the square root of a2+b2. It cannot be simplified. It is NOT a+b. The answer is c square.
It's the longest side. If a and b are the shorter sides, the square root of a squared plus b squared will equal the length of the hypotenuse
400-256 = b^2 144 = b^2 144^-2 [square root of 144] = b ? = b you can do the rest!
Because it is mathematically incorrect. a^2 + b^2 = c^2 Take square root of both sides. SQRT (a^2 + b^2) = c So you see, it is not a plus b equal c.
(A+B)2 = (A+B).(A+B) =A2+AB+BA+B2 =A2+2AB+ B2 So the Answer is A + B the whole square is equal to A square plus 2AB plus B square. Avinash.
if B*B = a, then B is square root of a
This question cannot be answered. You will have to give me the number to the square root. * * * * * a = ±sqrt(c^2 - b^2)
Nothing. You cannot have a square root of a negative number. The square root of negative one is called i, but i is an imaginary number. It does not exist and does not follow the properties of real numbers. (For example, if a and b are positive, then the square root of a times the square root of b is the square root of ab. But the square root of -7 is not the square root of 7 times i.)
Suppose that in the problem you describe, instead of a and b, we talk about actual numbers, such as 4 and 9. The square root of 4 is 2, and the square root of 9 is 3; so if we add the square root of 4 and the square root of 9, that is 2 + 3 = 5. Now, suppose we add 4 + 9 and get 13. The square root of 13 is just over 3.6, which you will note is considerably less than 5. This is because multiplication is not a linear process; as you multiply larger numbers, the total increases more rapidly than if you were merely adding numbers. A square root is the number which, multiplied by itself produces the number of which it is the square root, so it is basically connected to multiplication, not addition. Hence, you can't get the same result through addition.