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If 2 equations are perpendicular to one another they can have different y-intercepts, depending on how they are situated on a (x,y) graph.
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If a system of linear equations has exactly one solution then the two lines are what?
perpendicular
How wold you classify two linear equations have the same y-intercept and different slopes?
Two linear equations (or lines) with the same y-intercept and different slopes are intersecting lines. They intersect at the y-intercept. If the slopes are negative reciprocals (ex: one slope is 3 and one slope it -1/3) then they are perpendicular lines.
A system of two linear equations has exactly one solution if?
The slopes (gradients) of the two equations are different.
Determine whether the graphs of the equations are parallelperpendicular or neither?
Base on the slope of two linear equations (form: y = mx+b, where slope is m): - If slopes are equal, the 2 graphs are parallel - If the product of two slopes equals to -1, the 2 graphs are perpendicular. If none of the above, then the 2 graphs are neither parallel nor perpendicular.
Do equations with different slopes and different y-intercepts have a solution?
TWO linear equations with different slopes intersect in one point, regardlessof their y-intercepts. That point is the solution of the pair.However, this does not mean that three (or more) equations in two variables, even if they meet the above conditions, have a solution.
How can we tell if two lines are parallel perpendicular or neither just from their equations?
If the slope of the equations are the same then they are parallel If the slope of the equations are minus reciprocal then they are perpendicular If the slope of the equations are different then they are neither
Are perpendicular lines considered nonlinear?
No, two lines perpendicular to each other are wriiten as two separate equations. Both are linear.
If a system of linear equations has exactly one solution then the two lines are what?
perpendicular
How do you know when two equations will be perpendicular?
When they meet at right angles when plotted on the coordinated grid.
What makes two linear equations either parallel or perpendicular to each other?
Depending on the value of the slope or gradient if its the same then they are parallel if its a reciprocal then they are perpendicular.
How wold you classify two linear equations have the same y-intercept and different slopes?
Two linear equations (or lines) with the same y-intercept and different slopes are intersecting lines. They intersect at the y-intercept. If the slopes are negative reciprocals (ex: one slope is 3 and one slope it -1/3) then they are perpendicular lines.
A system of two linear equations has exactly one solution if?
The slopes (gradients) of the two equations are different.
Determine whether the graphs of the equations are parallelperpendicular or neither?
Base on the slope of two linear equations (form: y = mx+b, where slope is m): - If slopes are equal, the 2 graphs are parallel - If the product of two slopes equals to -1, the 2 graphs are perpendicular. If none of the above, then the 2 graphs are neither parallel nor perpendicular.
What is the different between one-step equations and two-step equations?
okay one step equations are when you do 1 problem and two step is when you do the same procedure twice
How do you find parallel perpendicular or neither?
parallel is easy. are they the same distance apart at two different benchmarks? if not then they may be perpendicular. perpendicular means they intersect at a 90 degrees. If it is any other angle and they are different distances apart at your two benchmarks then they are neither of the two choices
If two different lines are perpendicular to the same plane, they are?
Parallel.Parallel.Parallel.Parallel.
Do equations with different slopes and different y-intercepts have a solution?
TWO linear equations with different slopes intersect in one point, regardlessof their y-intercepts. That point is the solution of the pair.However, this does not mean that three (or more) equations in two variables, even if they meet the above conditions, have a solution.
