bt + 5b - 3t - 15 = b(t + 5) - 3(t + 5) = (t + 5)(b - 3)
It is: 5(a+b)
4(a+5b)
(a - 5b)(c - 5d)
5(3a - 5b + 4)
15a - 25b + 20 = 5 (3a - 5b + 4)
What integers add to -8 and multiply to 15? Sounds like -3 and -5, so: (a - 3b)(a - 5b)
6(b + 2)(5b - 2)
5b-15 = -10
5b + 5b = 2 x 5b
15 = 5b
What is the solution of -2a plus 3a plus 5b