d2/(d - c) + c2/(c - d) = d2/(d - c) - c2/(d - c) = (d2 - c2)/(d - c) = (d + c)(d - c)/(d - c) = d + c
C^ (2) - D^(2) Factors to (C -D )(C + D) If we apply FOIL to these bracketed terms. (C -D )(C + D), then we have F ; C^(2) O = CD I = -DC L = -D^(2) 'Stringing out' C^(2) + CD - DC - D^(2) NB Remember CD= DC ; just like 2 x 3 = 6 & 3 x 2 =6 Hence C^(2) + CD - CD _ D^(2) Adding terms we have C^(2) - D^(2) NB THe (+)CD - CD = 0 This is the inverse function, done to show how C^(2) - D^(2) factors. NB Remember two squared terms with a negative(-) between WILL Factor. However, two squared with a positive(+) between them does NOT factor. As a n example, take the Pythagorean Eq'n. h^(2) = x^(2) + y^(2) This does NOT factor . However, h^(2) - y^(2) = x^(2) Does factors to (h - y)(h + y) = x^(2) Hope that helps!!!!! d
Only 2: CD and DC.
Wattage = voltage times amperage. That's for DC. For AC there is a power factor PF = cos phi you have do multiply with.AnswerThe above answer suggests that power ('wattage') is an electrical unit, which it is not. In fact, power is defined as the rate of doing work, so the basic equation is work divided by time.
21.4
poopy brain blah blah
If you mean CD plus DC then in Roman numerals they add up to M meaning 400 plus 600 = 1000
No. Line CD is the same as line DC, but rays are always named from the origin point, so ray DC is a ray pointing in the opposite direction from ray CD.
No, they are different!
yes
No, they are different!
yes
Yes
yes
Yes
yes they are same.
CD and DC
Yes, line segments CD and dc are considered the same because they represent the same line segment regardless of the order of the endpoints. In geometry, the notation for a line segment does not depend on the sequence of the letters; both CD and dc denote the same path between points C and D.