84=42*2=6*7*2=2*3*7*2=4*7*3 2sqrt21
12 months in a year x 7 = 84 You could write A x B = 84
The common factors of 63 and 84 are: 1, 3, 7, and 21
Sqrt (7*12)sqrt (84)9.165
The prime factor decomposition of 84 is: 2 x 2 x 3 x 7 If you want to see my working (in case I made a mistake): 84/2=42 (42 is not prime), 42/2=21 (21 is not prime), 21/3=7 (7 is prime, so stop here) factors: 2,2,3 and 7
7 goes into 84 twelve times (84/7 = 12).
Yes, the answer is 7. Because 7 x 12 = 84
84 divided by 12=7
Yes. 84 is evenly divisible by seven.
84 is the answer. There is 12 in a dozen so 7 dozen is 7 * 12 = 84. If its a "bakers dozen" (which is 13) then it would be 7 * 13 = 91
1 and 7
7 goes into 84 12 times.
12 goes into 84 exactly 7 times with nothing left over
Their LCM is 84
588/7 = 84
7 goes into 84 twelve times exactly (ie there is no remainder).
84