9 reflection
Area of any circle = pi*radius2
The circumference of any circle is (pi) x (the circle's diameter).
a chord of the circle
One! I think...
A tetrahedron need not have any symmetry.
Parallelograms: 2-fold Square: 4-fold n-fold symmetries refer to rotational symmetries. Consequently, any symmetries about axes that these and other quadrilaterals may have are not relevant to this question.
The singular form of the plural noun symmetries is symmetry.
None, however the semicircle has one folding axis of symmetry perpendicular to the midpoint of the straight side
Fearful Symmetries - novel - was created in 1999.
Fearful Symmetries - 2016 was released on: USA: 2016
yes, in fact it can have 6 rotational symmetries.
Infinity Actually, The group of symmetries of a circle has elements of every finite order, as well as elements of infinite order. Each rotation of degree 360 / n , for some natural number n has an order of n.
Yes
It has 20
A circle, rotated through an angle measuring any real value in the interval [0, 360 degrees) or [0, 2*pi radians) and remain symmetrical. The order of symmetries is therefore the continuum, C - a number that is uncountably infinite (as opposed to countably infinite). No other 2-dimensional shape can match that. ***** The perimeter of a circle measured from the centre is the same length no matter where the measurement is taken.
For a star shaped figure, as many as the number of points. For a real star (like the ones up in the sky) either infinitely many or none - depending on the level of detail that you look at. The surface of any star has lots of dimples and bumps caused by stellar activity and these will break up any symmetry. If you ignore these fine details, then the star is a smooth ellipsoid and has infinitely many rotational symmetries. These symmetries are along the star's axis of rotation. For any other axis, the star's rotation will make the equatorial region bulge out and so there will be no symmetries.