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i(2i+5)(i-1) [I hope I've interpreted this correctly - WikiAnswers does not make it easy to pose mathematical questions!] First of all, multiply out in ordinary fashion: i(2i+5)(i-1) = i(2i2 + 3i - 5) = 2i3 + 3i2 - 5i Now, i is defined in this way: i2 = -1 Multiplying both sides by i we get: i3 = -i Substitute this information into the expression: 2i3 + 3i2 - 5i = -2i - 3 - 5i = -3 - 7i Done. ---- As the exponent of i is raised, incidentally, you will observe a cycle like this: i, -1, -i, 1, i, -1...
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