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(3z-2)^2=4

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Q: Find all real and imaginary solutions to each equation?
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What types of solutions can be found for linear equation?

A linear equation has a n infinite number of solutions. The coordinates of each point on the line is a solution.


What is the set of an equation in two variables in the set of all points in a coordinate plane that represent all the solutions of the equation?

To graph the set of all the solutions to an equation in two variables, means to draw a curve on a plane, such that each solution to the equation is a point on the curve, and each point on the curve is a solution to the equation. The simplest curve is a straight line.


What does all values of x are solutions mean?

Each value of x, when substituted in the equation, will give a true statement.


What is the extraneous solution to w equals sqrt 7w?

An "extraneous solution" is not a characteristic of an equation, but has to do with the methods used to solve it. Typically, if you square both sides of the equation, and solve the resulting equation, you might get additional solutions that are not part of the original equation. Just do this, and check each of the solutions, whether it satisfies the original equation. If one of them doesn't, it is an "extraneous" solution introduced by the squaring.


What are the solutions to the equation below (4x plus 36)(8x-40)0?

Assuming you mean:(4x+36)(8x-40) = 0 then you can use the property that a product can only be zero if one of its factors is zero. In other words, you can change this to: 4x + 36 = 0 OR 8x - 40 = 0 Solve each of the individual solutions; their solutions are also solutions to the original equation.

Related questions

How can you determine whether a polynomial equation has imaginary solutions?

To determine whether a polynomial equation has imaginary solutions, you must first identify what type of equation it is. If it is a quadratic equation, you can use the quadratic formula to solve for the solutions. If the equation is a cubic or higher order polynomial, you can use the Rational Root Theorem to determine if there are any imaginary solutions. The Rational Root Theorem states that if a polynomial equation has rational solutions, they must be a factor of the constant term divided by a factor of the leading coefficient. If there are no rational solutions, then the equation has imaginary solutions. To use the Rational Root Theorem, first list out all the possible rational solutions. Then, plug each possible rational solution into the equation and see if it is a solution. If there are any solutions, then the equation has imaginary solutions. If not, then there are no imaginary solutions.


How many solutions does a quadratic equation and an absolute value equation have?

They each typically have two solutions, a positive one and a negative one.


What is the result if you add 0 on each side of an equation?

The solutions of the equation (if any) remain unchanged.


How do you determine the solutions on a graph for a quadratic equation?

The X-Intercepts are the solutions. If you have an algebra calculator, you can usually find them by going to CALC>Zero>enter the left and right boundaries for each side.


What types of solutions can be found for linear equation?

A linear equation has a n infinite number of solutions. The coordinates of each point on the line is a solution.


How do you find 3 different ordered pairs that are solutions of the equation?

Select any three values of x in the domain of the equation. Solve the equation at these three points for the other variable, y. Then each (x, y) will be an ordered pair that is a solution of the equation.


What is the set of an equation in two variables in the set of all points in a coordinate plane that represent all the solutions of the equation?

To graph the set of all the solutions to an equation in two variables, means to draw a curve on a plane, such that each solution to the equation is a point on the curve, and each point on the curve is a solution to the equation. The simplest curve is a straight line.


What are some solutions to the equation 25x2-100 equals 0?

How many are you expecting ? How will you know if we give you all of them,or only some of them ?Since the highest power of the variable in the equation is '2', ("x2"),the equation has exactly two solutions.25x2 - 100 = 0Divide each side by 25:x2 - 4 = 0Add 4 to each side:x2 = 4Take the square root of each side:x = +4 and -4And there are your two solutions.


When you square each side of an equation is the resulting equation equivalent to the original?

No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2


What does all values of x are solutions mean?

Each value of x, when substituted in the equation, will give a true statement.


How do you solve systems of equations by graphing?

-- Graph each equation individually. -- Examine the graph to find points where the individual graphs intersect. -- The points where the individual graphs intersect are the solutions of the system of equations.


What is the extraneous solution to w equals sqrt 7w?

An "extraneous solution" is not a characteristic of an equation, but has to do with the methods used to solve it. Typically, if you square both sides of the equation, and solve the resulting equation, you might get additional solutions that are not part of the original equation. Just do this, and check each of the solutions, whether it satisfies the original equation. If one of them doesn't, it is an "extraneous" solution introduced by the squaring.