x - 18 = 34 just add 18 to both sides... X - 18 + 18 = 34 + 18 x + 0 = 52 x = 52
This number is 19(52)(52-1)(52-2)(52-3)(52-4)(52-5)(52-6)(52-7), or approximately 5.89 X 1014. The reasoning is as follows: Any one of the 19 freshman can be selected first. After this choice is made, there are 52 remaining persons (34 + 19 -1) from among whom the second position on the committee can be chosen, 52 -2 remaining persons for the third position, etc.)
The range is 46.
49 and 51 for example. Save 48; 52 47; 53 etc. Save
This questions can be rewritten as 52 choose 6 or 52C6. This is the same as (52!)/(6!(52-6)!) (52!)(6!46!) (52*51*50*49*48*47)/(6*5*4*3*2*1) 14658134400/720 20358520 There are 20,358,520 combinations of 6 numbers in 52 numbers. This treats 1,2,3,4,5,6 and 6,5,4,3,2,1 as the same combination since they are the same set of numbers.
47°34′3″N 52°42′26″W
34:52 is the ratio of 34 and 52.
52 - 47 = 5
52
34 is what percent of 52:= 34 / 52= 0.653846 or 65.3846%
Due to the fact that 52 is greater than 34, we know that the solution to this problem is going to be negative. So we find the difference between 34 and 52 (18), and make it negative. So the the answer is -18.
The increase from 47 to 52 is: 10.64%
The sum of 5 and 47 is 52.
34 multiplied by 52 is 1,768.
34÷100×52=17.68%
34/52 = 17/26
It is: 52-34 = 18