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What is the measure of the third angle of a triangle if one angle measures 97 degrees and the other mesures 45 degrees?
It is 38 degrees because 180-97-45 = 38
Suppose two angles are complementary If one angle has a measure of 62 what is the measure of the second angle?
If two angles are complementary, then they equal 90 degrees. If one angle is 62 degrees we subtract it from 90 and get 38 degrees.
What degrees is each interior angle of a 38 sided polygon?
Providing that it is a regular 38 sided polygon then each interior angle will measure: 170o31'34.74''
Find the missing angles for triangle ABC given that a equals 24 b equals 36 and c equals 19?
Trig. Use law of cosines in degree mode. First find alpha; the angle opposite a a^2 = b^2 + c^2 - 2bc*cos(alpha) 24^2 = 36^2 + 19^2 - 2(36)(19)cos(alpha) 576 = 1657 - 1368cos(alpha) subtract 1657 from both sides( order of operations ) -1088 = -1368cos(alpha) 0.7902046784 = cos(alpha) arccos(0.7902046784) = alpha 38 degrees = alpha ( angle opposite side a ) find beta; angle opposite side b b^2 = a^2 + c^2 - 2ac*cos(beta) 1296 = 937 - 912cos(beta) 359 = -912cos(beta) -0.3936403509 = cos(beta) arcos(-0.3936403509 = beta 113 degrees = beta ( angle opposite of b ) easy thing to get last angle 180 degrees - 38 degrees - 113 degrees = 29 degrees; which is gamma; angle opposite c alpha( angle opposite a side = 38 degrees beta( angle opposite b side ) = 113 degrees gamma(angle opposite c side) = 29 degrees
In a triangle the measure of the first angle is 24 degrees more than the measure of the second angle. The measure of the third angle is four times the measure of the second angle. If the total number?
Let the second angle be x degrees. The first angle would then be x + 24 degrees, and the third angle would be 4x degrees. According to the triangle angle sum theorem, the sum of all three angles in a triangle is 180 degrees. Therefore, you can set up the equation x + (x + 24) + 4x = 180 and solve for x to find the measures of all three angles.
