Using Pythagoras' theorem it is about 10.81665383 inches.
Width is 5.
Diagonal = 10 meters.
They are: 3 inches and 5 inches respectively
The dimensions are: length = 15 inches and width = 7 inches Check: 15*7 = 105 square inches
Width = 9 inches Length = 30 inches
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The diagonal length is about 18.44 inches.
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.
3.606 inches (rounded)
13 57/64 "
The width will be 30cm
The diagonal is 26cm
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The length of the diagonal is about 16.03 feet.
Width is 5.
The length of a rectangle is 8 inches. The width of the rectangle is 4 inches. What is the perimeter of the rectangle in inches?
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764