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What else can I help you with?
Find the length of the diagonal of a rectangular shaped book that has a length of 6 inches and width of 5 inches?
Diagonal = sqrt(36 + 25) ie sqrt 61 which is 7.8 inchesto the nearest tenth.
How do you find the measure of an angle to the nearest degree?
You can measure it. Or you can measure some other quantities (for examples, the lengths of the sides of a triangle), and calculate the angle using trigonometry.
How do you find the area of a circle to the nearest hundredth?
If you have the radius, then area = pi*r2 which you then round to the nearest hundredth. If you do not know the radius but do know the diameter or circumference, you can calculate the radius. Otherwise you need to measure it.
To the nearest degree find the measure of angle b in triangle abc given measure of angle a equals 48degrees ac equals 62cm and ab equals 61cm?
67 degrees
Find measure of each angle to the nearest tenth of a degreecosY equals 0.5135?
If cos y = 0.5135 then y = 59.1°.
Can you Find the length of the diagonal of a rectangle whose dimensions are fifteenm by sixm Approximate to the nearest hundredth?
I can and will. So if you put the diagonal through a rectangle you create a right angled triangle of which you can use pythagoras theorem. x2 = 152 + 62 x2= 261 x = 16.16m
What is the diagonal of a rectangle with a length of 127cm and a width of 76.20cm?
Use Pythagoras' theorem: 1272+76.22 = 21935.44 and the square root of this is 148.1061781 Answer: 148 to the nearest cm
The length of the rectangle below is 26.63 inches. If the diagonal makes an angle of 42.6 and ordm with this side find the measure of the width of the rectangle rounded to the nearest tenth of an inch?
The diagonal creates a right angled triangle with one pair of long and short sides - the diagonal is the hypotenuse. We know the angle between the long side (adjacent) and hypotenuse as 42.6°; We want to find the length of the short (width) side (opposite). We can use the Tan ratio: tan = opposite/adjacent → opposite = adjacent × tan → width = 26.63 in × tan 42.6° = 24.487... in → width is 24.5 inches to the nearest tenth of an inch.
What is the dimensions of a square whose diagional is 25 inches?
The diagonal of a square is usually found using Pythagoras's theorem, a2 + b2 = c2. Since this is a square, a = b; thus: c2 = 2s2, where s is the side length and c is the diagonal. s = square root(c2/2) = square root(625/2) = square root(312.5) = 17.8in The dimensions of a square whose diagonal is 25inches is 17.8in x 17.8in (rounded to the nearest tenth)
What is the area of the largest circle that will fit into a rectangle with dimensions 6.5 cm by 11.2 cm Use 3.14 as the approximation of pi and round your answer to the nearest tenth of a square cent?
The area of the WHOLE rectangle is less than 0.01 sq metres. So it is a lot less than a cent (which is 40 metres2 ). So to the nearest tenth of a cent, the area of the circle, which will be smaller than that of the rectangle, is 0. No calculations required.
What shape is a rectangle?
South Dakota.----Many have a rough shape of a rectangle, but Wyoming and Colorado seem to be nearest to a true rectangle.
What is the length to the nearest centimeter of a diagonal of a square 30 cm on a side?
42 cm
The length of a rectangle is 1 cm more than 4 times its width If the area of the rectangle is 97 cm2. find the dimensions of the rectangle to the nearest thousandth.?
Let the length be (4x+1) and the width be x: length*width = area (4x+1)*x = 97 4x2+x-97 = 0 Solving the above quadratic equation works out as: x = -5.051015124 or x = 4.801015124 it must be the latter because dimensions can't be negative. Therefore: length = 20.2 cm and width = 4.8 cm
How can you show that the area of a triangle half the area of the rectangle with the same base and height?
Draw a diagonal line across the rectangle. The resulting two right triangles will each have identical areas half that of the rectangle. The area of the rectangle is its height x base, and the area of each of the two triangles is 1/2 of its height x base.
What is the nearest half inch of a quadrangle?
Oh, what a delightful question! A quadrangle is a four-sided shape, like a square or rectangle. To find the nearest half inch, you simply measure the side lengths of the quadrangle and round to the nearest half inch. Remember, there are no mistakes in art, only happy little accidents!
How do you use a ruler to measure the nearest inch?
you need an object to measure to determine the nearest inch
A rectangular computer screen measures 40 centimeters by 50 centimeters To the nearest centimeter what is the length in centimeters of the diagonal of the computer screen?
The diagonal of a rectangle can be calculated using the Pythagorean theorem, which is a^2 + b^2 = c^2. In this case, a = 40 cm, b = 50 cm. So, c^2 = 40^2 + 50^2 = 1600 + 2500 = 4100. Taking the square root of 4100 gives us the diagonal, which is approximately 64 centimeters.
