Find the remainder when f(x) is divided by (x - k)
ƒ(x) = 2x3 + 3x2 + 4x + 18; k = -2
(x - k)
= (x - (-2))
= (x + 2)
x + 2 = 0
x = -2
By Remainder Theorem
ƒ(x) = 2x3 + 3x2 + 4x + 18
ƒ(-2) = 2(-2)3 + 3(-2)2 +4(-2) + 18
= 2(-8) + 3(4) + 4(-2) +18
= -16 + 12 -8 +18
= 6
Thus, the remainder is 6
85
-7
602 !
X = 8
x = -½
749 ÷ 4 = 187 remainder 1
7.8
8900
The answer would be 100, with 34 remainder.
Because there is no way to define the divisors, the equations cannot be evaluated.
Negative 17 plus 121 divided by 8 equals 13.
15 plus -3 equals 12 12 divided by -6 equals -2
It equals 0.172 with the two repeating.
32 divided by 4 equals 8 plus 4 equals 12 multipled by 8 equals 96 answer
No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.
7.3333
29From superscot 85: Not so, 29/5 = 5 remainder 4. The correct answer is 57 (plus all multiples of 60, eg 117, 177 etc)