If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x
-2
Get y by itself in standard form y = mx + b where m = slope and b = y intercept 2x + 4y - 10 = 0 4y = -2x +10 y = -2/4 x + 10/4 y = -1/2 x + 2.5 slope = - 1/2
the slope is in front of the x when solved for y.y=2x-3The slope is 2.
10-4=6
2x+y = 10 or y = -2x + 10 so the slope is -2
The slope is 3.
y-intercept is 10 slope is 3 over 1
It is: y = -0.4x+1 when in slope intercept form.
10 is.
y= -4x + 10 Slope intercept form is y=mx+b
y = -2x+10
I won't tell you directly, but I will explain how to find out to you. In the type of equation you are faced with now (y=mx+b), m represents the slope. So, in y=3x+10, the slope is 3. Now, find the slope of the other equation and see which is greater. Lines with greater slopes are steeper.
y + x = -10Subtract 'x' from each side:y = -x -10The slope is -1 .
If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x
It has infinite slope.
It is a straight line equation which can be rearranged to y = 3x+10 in slope intercept form