answersLogoWhite

0


Best Answer

Let the intgers be n- 1 n , & n+1 . This is consecutive.

Hence

Adding

(n-1) + n + ( n +1) = 126

Add the LHS

3n = 126

Divide both sides by '3'

n = 42

Hence n- 1 = 41

& n +1 = 43

So the consecutive integers are 41,42, & 43.

User Avatar

lenpollock

Lvl 16
2y ago

Still curious? Ask our experts.

Chat with our AI personalities

RafaRafa
There's no fun in playing it safe. Why not try something a little unhinged?
Chat with Rafa
ViviVivi
Your ride-or-die bestie who's seen you through every high and low.
Chat with Vivi
JudyJudy
Simplicity is my specialty.
Chat with Judy
More answers
User Avatar

Wiki User

10y ago

The integers are 41, 42 and 43. Also, using consecutive even integers, you find: 40, 42 and 44.

User Avatar

Add your answer:

Earn +20 pts
Q: Find three consecutive integers whose sum is 126?
Write your answer...
Submit
Still have questions?
magnify glass
imp