Let the intgers be n- 1 n , & n+1 . This is consecutive.
Hence
Adding
(n-1) + n + ( n +1) = 126
Add the LHS
3n = 126
Divide both sides by '3'
n = 42
Hence n- 1 = 41
& n +1 = 43
So the consecutive integers are 41,42, & 43.
lenpollock
Wiki User
∙ 2014-08-06 14:48:38The integers are 41, 42 and 43. Also, using consecutive even integers, you find: 40, 42 and 44.
Those three odd integers are 43, 45, and 47.
99, 100, and 101
42, 44, 46.
-2 + -3 + -4 = -9
The numbers are -134, -132 and -130.
find three consecutive integers whose sum is - 93
Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43
No. There is no set of three consecutive even integers with a sum of 40.
The integers are 19, 20 and 21.
The integers are 16, 17 and 18.
The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.
The even integers are 22, 24 and 26.
Those three odd integers are 43, 45, and 47.
Those three odd integers are 43, 45, and 47.
-9, -10 and -11.
99, 100, and 101
31, 32 and 33