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Let the intgers be n- 1 n , & n+1 . This is consecutive.
Hence
Adding
(n-1) + n + ( n +1) = 126
Add the LHS
3n = 126
Divide both sides by '3'
n = 42
Hence n- 1 = 41
& n +1 = 43
So the consecutive integers are 41,42, & 43.
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