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Let the intgers be n- 1 n , & n+1 . This is consecutive.
Hence
Adding
(n-1) + n + ( n +1) = 126
Add the LHS
3n = 126
Divide both sides by '3'
n = 42
Hence n- 1 = 41
& n +1 = 43
So the consecutive integers are 41,42, & 43.
What else can I help you with?
Find three consecutive odd integers whose sum is 135?
Those three odd integers are 43, 45, and 47.
Find three consecutive even integers whose sum is 132?
42, 44, 46.
Find three consecutive integers whose sum is - 9?
-2 + -3 + -4 = -9
Find three consecutive even integers whose sum is -396?
The numbers are -134, -132 and -130.
Find three Consecutive odd integers whose sum is 117?
117/3 = 39, so the three consective odd integers whose sum is 117 are 37, 39, and 41.
Is it possible to find three consecutive even integers whose sum is 40?
No. There is no set of three consecutive even integers with a sum of 40.
Find three consecutive integers whose sum is 60?
The integers are 19, 20 and 21.
Find three consecutive integers whose sum is 51?
The integers are 16, 17 and 18.
Find three consecutive integers whose sum is -108?
The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.
Find three consecutive odd integers whose sum is 135?
Those three odd integers are 43, 45, and 47.
Find three consecutive odd integers whose sum is (-75)?
Those three odd integers are 43, 45, and 47.
Find three consecutive even integers whose sum is 72?
The even integers are 22, 24 and 26.
Find three consecutive integers whose sum is -42?
They are -15, -14 and -13.
Find three consecutive integers whose sum is -21?
-6, -7, and -8.
Find Three consecutive integers whose sum is -15?
a+(a+d)+(a+2d)=-15
Find three consecutive integers whose sum is 96?
31, 32 and 33
Find three consecutive integers whose sum is -30?
-9, -10 and -11.
