Find three consecutive odd integers whose sum is 33?

Answer 1

9,11,13.

Here's how:

x=lowest#in consecutive #s

x+(x+2)+(x+2+2)=33.

addition is associative so: x+x+2+x+2+2=33

group the #s and x's:3x+2+2+2=3x+6=33

Subtract integers:3x=27

divide:x=9

And take the next two odd integers.