Find three consecutive odd integers whose sum is 33?

Updated: 4/28/2022

x=lowest#in consecutive #s

x+(x+2)+(x+2+2)=33.

addition is associative so: x+x+2+x+2+2=33

group the #s and x's:3x+2+2+2=3x+6=33

Subtract integers:3x=27

And take the next two odd integers.

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Those three odd integers are 43, 45, and 47.

99, 100, and 101

-2 + -3 + -4 = -9

The numbers are -134, -132 and -130.

No. There is no set of three consecutive even integers with a sum of 40.

The integers are 19, 20 and 21.

The integers are 16, 17 and 18.

The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.

Those three odd integers are 43, 45, and 47.

Those three odd integers are 43, 45, and 47.

The even integers are 22, 24 and 26.

99, 100, and 101

They are -15, -14 and -13.

-6, -7, and -8.

a+(a+d)+(a+2d)=-15

31, 32 and 33

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