How can i write and equation of the line that passes through the givin point and is parallel to the givin line 0-8 8x 4y 5?

Answer 1

Write the equation of the line that passes through the point (0, 8) and is parallel to the line with equation 8x + 4y = 5.

Solution

Two lines are parallel if they have the same slope.

First, we write the slope-intercept form for the given line:

8x + 4y = 5 subtract 8x to both sides;

4y = -8x + 5 divide by 4 to both sides;

y = -2x + 5/4

So, the slope of the two lines is -2.

By using the point (0, 8), we can write the point-slope form of the required line:

(y - y1) = m(x - x1)

(y - 8) = -2(x - 0)

y - 8 = -2x add 8 to both sides;

y = -2x + 8 add 2x to both sides;

y + 2x = 8 or

2x + y = 8

This is the general form of the line that passes through the point (0, 8) and is parallel to the line 8x + 4y = 5