x^2 - 6x + 5x + 7 = 0 => x^2 - x + 7 = 0The roots of this equation are
0.5 - 2.5981*i and 0.5 + 2.5981*i where iis the imaginary square root of -1.
It can't be solved because the discriminant of the given quadratic equation is less than zero.
5x-3 = 11+12x 5x-12x = 11+3 -7x = 14 x = -2
Then x = 6 Therefore; 5x + 3 = 33 First you have to solve the value of X: 8X + 5X + 2X +4X = 114; OR 19x = 114. When you divide both sides of the equation by 19 to solve for X, you find that X = 6. Ergo, 5X + 3 = 30 + 3 = 33; hence, 5X + 3 = 33.
3x + 2x = 5x. 5x= (-4) X = (-4)/5 x= -0.8
4x - 3 - 5x + 7 = 6 4x - 5x = 3 - 7 + 6 -1x = 2 x = -2
You cannot solve 1 linear equation in 2 unknown variables. You need at least two independent equations.
you cant
23
7
x = -8
3
x = -1.2, y = -3
-5x+50 = 25 -5x = 25-50 -5x = -25 x = 5
x=35
172=x
You find x. Oh! There it is!! ^ See?
5x + 2 = 22 5x = 22 - 2 5x = 20 5x/5 = 20/5 x=4
5x+y=-7 3x+y=15 8=D