Area = LxW Using the figures you have 56 = L x 7 L = 56/7 L = 8
The formula for the area of a rectangle is length x breadth. In order to prove this works, work out an area of a rectangle using that formula.
You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.
L = 5W 2L + 2W = 72 ==> L + W = 36 Substitute L = 5W: 5W + W = 6W = 36. ==> W = 6, and L = 30. Area = 180
Find the area of all of it, then devide by 2.
Area of rectangle is l x b. Where l is length and b is breath of the rectangle.
Area of a rectangle: a = l * w
W = width of rectangle L = length of rectangle A = area of rectangle W x L = A (L+11) x L = A L squared + 11 L - 1302 = 0 solve for L by quadratic equation or by factoring: (L-31)(L +42) = 0 L = 31 W = L+11 = 42
Area of a rectangle in square units = length*width
yes the formula is L x 2 you work it out the same as you would a rectangle
The surface area is L*B where L is the length of the rectangle and B is the breadth.
In order to find the area of a rectangle, you must follow the formula A= l x w where A is area, l is length, and w is width.
the formula for a rectangle is L x W where L is length and W is width.
MULTIPLICATION area for a rectangle is A = L * W * H where, A = area of rectangle L = Length of rectangle W = width of rectangle H = height of rectangle The dimensions of a rectangle (L, W, and H) are interchangeable because they are being multiplied together and hence each side of the rectangle can be arbitrarily assigned to a dimension.
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
A square is a special form of a rectangle where Length = Width. So L*W for a square would be L*L = L^2 where L is the length of a side.
Represent the length of the rectangle by L and the width by W. The perimeter = 2L + 2W = 2(L + W). The area = L x W.