This is the matrix im talking about [A B]
[C D]
For a 2x2 matrix if the f***ing AD-BC does not = 0 thennnn theres an inverse!!!!
Sooo........
Use this equation!!!
1/(AD-BC) multiplied by the matrix [D -B] <----- this is 1
[C -A] <----matrix!! and so is the one above
mother f***!!!
try it
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Let A by an nxn non-singular matrix, then A-1 is the inverse of A. Now (A-1 )-1 =A So the answer is yes.
If an identity matrix is the answer to a problem under matrix multiplication, then each of the two matrices is an inverse matrix of the other.
A matrix A is orthogonal if itstranspose is equal to it inverse. So AT is the transpose of A and A-1 is the inverse. We have AT=A-1 So we have : AAT= I, the identity matrix Since it is MUCH easier to find a transpose than an inverse, these matrices are easy to compute with. Furthermore, rotation matrices are orthogonal. The inverse of an orthogonal matrix is also orthogonal which can be easily proved directly from the definition.
A non-square matrix cannot be inverted.
of course it does