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By applying the conjugate.

e.g.

6 / sqrt(2) = (6sqrt(2)) / (sqrt(2)*sqrt(2)) =>

(6sqrt(2)/ 2=>

3sqrt(2) The answer.

Or a more complex calculation.

( 6 - sqrt(5)) / (2 - sqrt(3))

The conjugate is 2 + sqrt(3) ; Apply top and bottom.

(6 - sqrt(5))(2 + sqrt(3)) / (2 - sqrt(5))(2 + sqrt(5))

We now use FOIL (Like multiplying two brackets together) .

(12 -2sqrt(5) + 6 sqrt(3) - sqrt(15)) / (4 - 2sqrt(5) + 2 sqrt(5) - 5) (

12 -2sqrt(5) + 6 sqrt(3) - sqrt(15)) / ( - 1)

-12 + 2sqrt(5) - 6qrt3) + sqrt(15) This cannot be taken any further!!!!

Hope that helps with division of radicals.

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lenpollock

Lvl 16
3y ago

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