If you mean that the lines intersect in a point then it can't be done. At least not in a plane assuming Euclidean geometry.
Proof:
We draw up a system of coordinates on the plane so that the two first intersecting lines can be represented by the equations
Since the lines intersect in a point a must not equal c, since those numbers determine the relative angle of the lines, and if a = c the line would be parallel - thus never intersect - or they would intersect in all points along any of the lines.
Now, to introduce another line which neither intersects y1 nor y2, we set up the following:
Together with what we established earlier, that a =/= c we can easily see the impossibility in e = a being true at the same time as e = c. Thus the third line must intersect at least one other line.
QED
If you have one angle, you can draw two line segments that meet at that angle. Then, rotate your paper 180 degrees, and repeat, ensuring that the new lines are parallel to the existing ones, and eventually intersect them. You now have a parallelogram.
perpendicular lines intersect each other at 90 degrees whereas parallel lines never intersect each other and remain equal distance apart from each other. Obviously the way to test if two lines are parallel is to measure their distance from each other at at least two points (the farther apart the better) to confirm that they remain equal distance apart, but to test if lines are perpendicular, with a compass with the point at the point where the two lines intersect, draw an arc (or three parts of an arc) that intersects one of the lines in two places and the other line in one place. If the distances between the lines at the points where they are intersected by the arc are equal, the lines are perpendicular.
you draw a square with 3 lines inside it.
Well the easiest way to do this (but in no way perfectly accurate) would be to extend both lines as far as you can on either end. If the lines never meet on either side you've got parallel lines. Well, either that or you're not drawing straight lines, or you haven't drawn them out far enough. The accurate way would be to draw a perpendicular line from one of them towards the other and measure the angle against the second line. If it's perpendicular to both lines you've got yourself parallel lines.
Drawing perpendicular bisector for a line:Place the sharp end of a pair of compasses at one end of the line, and open it to just over half of the line. Draw an arc which must intersect the line in the position described. Then put the sharp end at the other of the line and, keeping the compassing at the same length, draw another arc which intersects the first one twice and also the line. Then draw a straight line through the two places where the arcs intersect. This line is the perpendicular bisector. Drawing perpendicular bisector of angle:Places the sharp end of the compass at the point of the angle and, after having opened it arbitraily wide, draw an arc which intersects the two lines meeting to form the angle each once in the said position. Then remove the compass and, always keeping it opened at the SAME length, place the sharp end at each of the two places where the previous arc cuts each of the two lines meeting to form the angle. In this position with the described length, draw a small arc at each of the said places, which should cross each other. Draw a straight line from the point of the angle to this crossing. This should be the bisector of the angle.
Just draw one line and draw another one over that to make it look like some kind of 'X'. The two lines are intersected.
That's impossible because a polygons lines cannot intersect
First you draw a big multiplication sign, and then you draw another line vertical to the right of the sign (so it intercects both lines), and then you draw the final line horizontally above the sign (so it intercects all three lines), and you have 6 points of intercection :)
- If you're working on a single sheet of paper (2-D), then you can draw four lines that intersect in 1, 2, 3, 4, 5, or 6 points. - If in 3-D space, then you can also draw four lines that don't intersect at all.
Parralel Lines.
draw the diameter draw a line making a 30 degrees angle from one side of the diameter draw another one making a 30 degrees angle from the other side of the diameter join the points where these two lines intersect the circle.
Draw a straight line segment. From one of its ends, draw another straight line segment. From the end of this straight line, draw another straight line segment which does not touch any of the existing lines. Repeat the same 5 more times. From the end of this last line, draw a straight line to the start of the first line. You may need to tweak some of the intermediate lines so that the last line does not intersect an existing line. That is it! A plane area enclosed by 9 straight lines = a 9-sided polygon.
If you draw two lines intersecting, you'll see that they create 4 angles.
Yes, if you draw a line between the bases, these lines intersect at right angles.
Yes. Draw a triangle without its base line. From both the base vertices draw a line to the opposite side(somewhere in the middle). The four lines so created will meet in 6 points.
Parallel lines are lines that, if extended, would never intersect with eachother. This means that they are going in the same direction, eg. | |, but not | \. Horizontal means that that are going across, eg. ___________________, not |. An example of a lines that are parallel and horizontal: _____________________________________ _____________________________________
If by parallel, you mean two lines that do not intersect, yes, it is possible to draw them on the surface of a sphere. They will end up being circles, and most pairs will not be equal in size. If you add the idea that the two lines also continue to infinity to the definition, then you cannot draw such things on the surface of a sphere.