Oh, what a happy little math problem we have here! To factor 35x + 63y, we can first look for the greatest common factor of the coefficients, which is 7. Then we can factor out the 7 to get 7(5x + 9y). And just like that, we've created a beautiful and simplified expression!
7(5x + 4y)
5x2
35x + 15x = 50x
1. 3x2+12= 3(x2+4) 2. 7x2+35x= 7x(x+5)
There are an infinite number of expressions equivalent to that one. 3(x + 3y + 5) would be one such example, (x/7)(21 + 63y/x + 105/x) would be another.
7(5x + 9y)
25x + 35x + 9 is 60x + 9, which factors to 3(20x + 3)
7(5x + 4y)
It is an algebraic expression
The GCF is 9.
x^(3) - 12x^(2) + 35 x Factor out 'x' Hence x(x^(2) - 12x + 35) Factor the quadratic x(x - 5)(x - 7) Done!!!!!
35x + 115 = 360 35x = 360-115 35x = 245 x = 245/35 x = 7
42x+35x-35x=42x it's leave 85 so it's change into a negative 42x-85 is the answer
35x + 10
(7x-3)(2x+5) 14x2 + 29x - 15, write 29x = 35x - 6x = 14x2 - 6x + 35x - 15 = (14x2 - 6x) + (35x - 15) = 2x(7x - 3) + 5(7x - 3) = (7x-3)(2x+5)
x3 + 2x2 - 35x = x(x + 7)(x - 5)
5x2