A quadratic function is of the form:
f(x) = ax2 + bx + c where a ≠0
If a > 0 then the quadratic has a minimum but its maximum, asymptotically, is +∞.
If a < 0 then the quadratic has a maximum but its minimum, asymptotically, is -∞.
The extremum (whichever it is) is attained when x = -b/2a.
The extreme value is f(-b/2a) = a*(-b/2a)2 + b(-b/2a) + c
= b2/4a - b2/2a + c = -b2/4a + c
It is max(z1,...,z10)/min(z1,...,z10).
120 mi/hr * 1/60 hr/min = 2 mi/min
8. 8(number of min.) x _ = 64 (number of min.) 8x_=64 and _=8
1 hr=60 min or 60 min=1 hr or 1 min=1/60 hr ==>13min=13/60hr now, speed = distance/time = 2.6X13/60 = 0.564 km/hr or 0.564X5/18 m/s = 0.156 m/s.
700 gal/ 20 min = 35 gallons/ 1 min * 60 min/ 1 hour= 2100 gallons per hour.
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
int sum (int min, int max) {return (max-min+1)*(max+min)/2;}
Find the minimum and maximum of what? An array?
int a, b, c, d, max, min; scanf("%d%d%d%d",&a, &b, &c, &d); (a>b)?(max=a,min=b):(max=b,min=a); (c>d)?(a=c,b=d):(a=d,b=c); max=(a>max)?a:max; min=(b<min)?b:min; printf("%d %d\n", max, min);
The min and max is when the first derivative , or slope at any point, is zero. For f of x = 2x first derivative is 2, so this is constant slope with no min or max as this is not zero; min is thus negative infinity and max is infinity
=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)
Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. sonika aggarwal GNIIT
You take the integral of the sin function, -cos, and plug in the highest and lowest values. Then subtract the latter from the former. so if "min" is the low end of the series, and "max" is the high end of the series, the answer is -cos(max) - (-cos(min)), or cos(min) - cos(max).
take the max plus the min and divide the anser by to
pyrometer reading is fluctuating between min to max range
MIN is used to find the lowest number in a range. You would use MAX or LARGE to find the highest number in a range.
The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)