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A quadratic function is of the form:
f(x) = ax2 + bx + c where a ≠0
If a > 0 then the quadratic has a minimum but its maximum, asymptotically, is +∞.
If a < 0 then the quadratic has a maximum but its minimum, asymptotically, is -∞.
The extremum (whichever it is) is attained when x = -b/2a.
The extreme value is f(-b/2a) = a*(-b/2a)2 + b(-b/2a) + c
= b2/4a - b2/2a + c = -b2/4a + c
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What formula with functions can you enter to calculate the ratio of the maximum value in the range z1z10 to the minimum value?
It is max(z1,...,z10)/min(z1,...,z10).
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A tanker ship is off-loading its oil tank at a terminal It takes 20 minutes to fill a 700 gallon tank What is the average flow rate of oil into the truck in gallons per hour?
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How do you determine if the graph of a quadratic function has a min or max from its equation?
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
Write a c program to find the sum of numbers between given limits?
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How to find max and min values?
Find the minimum and maximum of what? An array?
How do you find the largest and the smallest values among 4 numbers using conditional operators?
int a, b, c, d, max, min; scanf("%d%d%d%d",&a, &b, &c, &d); (a>b)?(max=a,min=b):(max=b,min=a); (c>d)?(a=c,b=d):(a=d,b=c); max=(a>max)?a:max; min=(b<min)?b:min; printf("%d %d\n", max, min);
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What formula with functions in Excel can you enter to calculate the ratio of the maximum value in the range Z1 to Z10 to the minimum value?
=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)=MAX(Z1:Z10)/MIN(Z1:Z10)
What is max thermometer and min thermometer?
An instrument used to find out the air temperature
Trace out the algorithm Max Min on a data set containing atleast 8 elements?
Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. sonika aggarwal GNIIT
How do I get max to min serial or What function can I use to get max to min or min to max serial?
it will orbit the sun it self and the sun will keep it in the right spot for its temperature
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You take the integral of the sin function, -cos, and plug in the highest and lowest values. Then subtract the latter from the former. so if "min" is the low end of the series, and "max" is the high end of the series, the answer is -cos(max) - (-cos(min)), or cos(min) - cos(max).
How do you find the mean in a set of data?
take the max plus the min and divide the anser by to
Where to find repair for pyrometer?
pyrometer reading is fluctuating between min to max range
