How do you find the prime factorization of 88?

Answer 1

We note that '88' is an even number, because it ends in '8' , an even number.

So it will divide by '2'

Hence

2)88

2)44

2)22

11)11

=1

Reduce to '1'

Then the prime factors are 2 x 2 x 2 x11 = 2^(3) x 11

Answer 2

Find 2 factors of 88. Now break those factors into smaller factors and keep on doing it until you have a Prime number and can't break it. (88: 22 and 4) (22= 11x2 4= 2x2) (11x2x2x2)