The solution relies on using the sine rule.Suppose that the perimeter of triangle ABC is P.Then you need to divide P into 3 parts in the ratio of sin(A) : sin(B) : sin(C).Let sin(A) + sin(B) + sin(C) = X. ThenAB = P*sin(C)/XBC = P*sin(A)/XCA = P*sin(B)/X
The longest side of the triangle will always be opposite the largest angle, which is 90° in this case. We can use the sine law to work out the other sides with that: sin(90°) / 18 = sin(60°) / x = sin(30°) / y 1/18 = sin(60°) / x x = 18 sin(60°) x = 18√3 / 2 x = 9√3 1/18 = sin(30°) / y y = 18 sin(30°) y = 9 So the triangle has a sides of 9 and 9√3, with a hypotenuse of 18
sin θ = cos (90° - θ) cos θ = sin (90° - θ)
An equilateral triangle has 3 equal interior angles each of 60 degrees. There are two right angled triangles in an equilateral triangle. So we can use trigonometry to find the length of one side of the equilateral triangle then multiply this by 3 to find its perimeter. Hypotenuse (which is one side of the equilateral) = 15/sin 60 degrees = 17.32050808 17.32050808 x 3 = 51.96152423 Perimeter = 51.96152423 units.
sin of angle a = opposite/hypotenuse = 1/3 sin-1(1/3) = 19.47122063 degrees
Sin is the opposite over the hypotenuse.
Sin is sin-1(opposite/hypotonose)
sin, tan and cos can be defined as functions of an angle. But they are not functions of a triangle - whether it is a right angled triangle or not.
Area of an equlateral triangle = 0.5*side2*sin(60)
Answer the answer is Herons formula:Area=sqrt(sin(sin-a)+(sin-b)+(sin-c) where a ,b, c are the measurement of the sides.just input the measurement of the sides in the formula and you will have your answer.here you can calculate the area of a triangle with out height.
The solution relies on using the sine rule.Suppose that the perimeter of triangle ABC is P.Then you need to divide P into 3 parts in the ratio of sin(A) : sin(B) : sin(C).Let sin(A) + sin(B) + sin(C) = X. ThenAB = P*sin(C)/XBC = P*sin(A)/XCA = P*sin(B)/X
If you have angles, use the sine rule: a/sin A = b/sin B = c/sin C a denotes the side, A the angle opposite the side.
No. An equiangular triangle is always equilateral. This can be proven by the Law of Sines, which states that sin A / a = sin B / b = sin C / c, where A, B and C are angles of a triangle and a, b and c are the opposing sides of their corresponding angles. If A = B = C, then sin A = sin B = sin C. Therefore for the equation to work out, a = b = c. Therefore the eqiangular triangle is equilateral, and therefore not scalene, which requires that all sides of the triangle be of different lengths.
You can use trigonometry: sin α = opposite/hypotenuse, cos α = adjacent/hypotenuse, tan α = sin α/ cos α and using the law of sines:a/sin a = b/sin b = c/sin c. From all these you can derive equations to help you solve your task. Also if you have two angles and a triangle you actually have three angles α + β + γ = 180 in a triangle
Area of equilateral triangle: 0.5*7*7*sin(60 degrees) = 21.2 square inches
Do you mean an equilateral triangle? Then if so then the formula for the area of any triangle: 0.5*a*b*sinC whereas a and b are the embraced sides of angle C And in the case of an equilateral triangle it is: 0.5*any side squared*sin(60 degrees) Alternatively use Pythagoras' theorem to find the altitude of the triangle then use: 0.5*base*height = area
The sine of an angle is obtained from a right angle triangle. The other two angles are acute, or less than 90 degrees. The sin of the angle is the side opposite the angle divided by the hypotenuse.