The value of m is the slope and the value of b is the y intercept.
y = 6 - xThe slope is -1 .The y-intercept is y=6 .
Remember the standard form of an equation:Y = (slope) x + (y-intercept)Now take your equationY = (-1) x + (0)Compare yours to the standard one.That's how to find them.Now can you identify the slope and y-intercept of the graph of your equation ?
The slope intercept form is y=mx+b where m is the slope and b is the y intercept y=2x-8.
Convert the equation into standard form, y = mx + c, where m is the slope and c is the y intercept. -2x - 8y = 16 8y = -2x - 16 y = - x/4 - 2 Then the slope is -1/4 and the y intercept is -2
slope = 31 and intercept = 4
The value of m is the slope and the value of b is the y intercept.
The slope is 1/3 and the y-intercept is -1.
y = -2x+5 Slope: -2 Intercept: 5
Since your equation is already in slope-intercept form, it's easy. Slope-intercept form is as follows: y=mx+b m always ends up being your slope, and b is your y intercept. Slope = 5, and the y intercept = 8 in your equation.
There is no y intercept, it is a straight verticle line a x = -6. And technically it has "infinite" slope (1/0), but it is more common to say "No slope".
3x + y = 5 y = -3x + 5 slope is -3 and y intercept is 5.
You have to find the slope and y-intercept first.
slope = -4 for y=mx+c, slope=m, y intercept=c
y = 6 - xThe slope is -1 .The y-intercept is y=6 .
Remember the standard form of an equation:Y = (slope) x + (y-intercept)Now take your equationY = (-1) x + (0)Compare yours to the standard one.That's how to find them.Now can you identify the slope and y-intercept of the graph of your equation ?
5.5