The arithmetic sequence of odd integers is 1, 3, 5, 7, 9, ... where the common difference is 2. The sum of the first thirty odd integers can be found by using the sum formula such as:
Sn = n/2[2a1 + (n - 1)d], where a1 = 1, n = 30, and d = 2. So,
S30 = (30/2)[(2)(1) + (30 - 1)(2)] = (15)[2 + (29)(2)] = (15)(60) = 900
The sum of the first eleven positive odd integers is 121.
find the two consecutive odd integers with a sum of 152
The sum of the first positive odd integers less than 101 is 10,000.
Those three odd integers are 43, 45, and 47.
The sum of two consecutive odd integers is an even number. There is no possible answer to this question.
The integers are -12, -10 and -8.
The sum of the first eleven positive odd integers is 121.
The sum of the first 2,006 positive, odd integers is 4,024,036.
The first odd positive integers are "1" and "3" which the sum is 4.
find the two consecutive odd integers with a sum of 152
The sum of the first 5,000 odd, positive integers is 5,000 squared or 25,000,000.
The sum of the first 230 positive, odd integers is 230 squared or 52,900.
The numbers are -13, -11, and -9.
The sum of the squares of the first 1000 positive odd integers (from 12 to 19992) is 1333333000.
The sum of the first positive odd integers less than 101 is 10,000.
Yes. The sum of the first 5,000 odd, positive integers is 25,000,000 (25 million).
Those three odd integers are 43, 45, and 47.