50 = 5x3 + 45x7/15 + 315-301. You can see from this that there is an infinite number of ways of getting the last pair of odd numbers with a difference of 14.
You could use the useful trick that for 3 equally spaced numbers a, b, c, then the result of a-b+c is always b, and a+b+c is 3b. So you could have 47 + (7-9+11)/(1-3+5), or 47 + (7+9+11)/(1+3+5). There is an infinite number of ways of using that trick. (I assume that by "7 odd numbers" you mean "7 different positive integers not divisible by 2 exactly").
Start out looking at them. 7x1=7 odd 7x2=14 even 7x3=21 odd 7x4=28 even 7x5=35 odd 7x6=42 even... so it looks like half might be even and half odd, This is because if we look at the numbers 1-14, ie 1,2,3,4,5,6,7,8,9,10,11,12,13. and 14, they alternate odd and even and since 7 is odd and odd times an even is always an even number and an odd times an odd is always an odd number. So to answer the question we need only look at the number of odd numbers between 1 and 14 inclusive. There are 6 so 1,3,5,7,9,11,13 give odd multiples ANSWER: so 7 odd multiples of 7 between 1 and 100
55 is an odd number. Odd numbers end in 1, 3, 5, 7, or 9. Even numbers end in 0, 2, 4, 6, or 8.
7 and 9 72+92 = 130
No, 34 is an even number. Even numbers end in 0, 2, 4, 6, or 8. Odd numbers end with 1, 3, 5, 7, or 9.
it goes by odd numbers, 2 + 3= 5, 5+5=10, 10 + 7=17 the rest of the pattern is 26, 37, and 50
It is not possible. The sum of 7 odd numbers must be odd while 50 is not odd.
Multiply 7 by any odd number, then check whether the result is between 5 and 50.
The nine odd numbers whose sum is 50 are 1, 3, 5, 7, 9, 11, 13, 15, and 1.
There is no way without playing silly games. Each of the numbers in the list is odd. The sum of five odd numbers must be odd and therefore, cannot be 50. There is no way without playing silly games. Each of the numbers in the list is odd. The sum of five odd numbers must be odd and therefore, cannot be 50. There is no way without playing silly games. Each of the numbers in the list is odd. The sum of five odd numbers must be odd and therefore, cannot be 50. There is no way without playing silly games. Each of the numbers in the list is odd. The sum of five odd numbers must be odd and therefore, cannot be 50.
There are 7 odd numbers between 50 and 64. To find this, we first identify the odd numbers in the range, which are 51, 53, 55, 57, 59, 61, and 63. We can calculate the count by subtracting the first odd number (51) from the last odd number (63) and then adding 1 (63-51+1=13+1=7).
47 and 3 43 and 7
You cannot do this, because you're taking odd numbers: if you add two odd numbers together, you will get an even number. Take the odd numbers in pairs, so you'll have 3 pairs plus an extra odd number. The 3 pairs make 3 even numbers. You can add up any number of even numbers and get an even number, so you will have an even + odd, which is odd. 30 is an even number, but your result will be odd, no matter what 7 odd numbers you choose.
odd multiples of 7 are odd numbers.. like 7*1, 7*3,7*5..
The odd prime numbers from 1 to 50 are 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, and 47.
(9 ÷ 3 + 7) x 1 x 5 = 50
The product (result of multiplication) is always odd. For example: 3*3=9 5*5=25 7*7=49
Sure and beginning with number 51. All numbers that end with 1, 3, 5, 7, 9 are odd no matter how high the number is !