50 = 5x3 + 45x7/15 + 315-301. You can see from this that there is an infinite number of ways of getting the last pair of odd numbers with a difference of 14.
You could use the useful trick that for 3 equally spaced numbers a, b, c, then the result of a-b+c is always b, and a+b+c is 3b. So you could have 47 + (7-9+11)/(1-3+5), or 47 + (7+9+11)/(1+3+5). There is an infinite number of ways of using that trick. (I assume that by "7 odd numbers" you mean "7 different positive integers not divisible by 2 exactly").
Chat with our AI personalities
Start out looking at them. 7x1=7 odd 7x2=14 even 7x3=21 odd 7x4=28 even 7x5=35 odd 7x6=42 even... so it looks like half might be even and half odd, This is because if we look at the numbers 1-14, ie 1,2,3,4,5,6,7,8,9,10,11,12,13. and 14, they alternate odd and even and since 7 is odd and odd times an even is always an even number and an odd times an odd is always an odd number. So to answer the question we need only look at the number of odd numbers between 1 and 14 inclusive. There are 6 so 1,3,5,7,9,11,13 give odd multiples ANSWER: so 7 odd multiples of 7 between 1 and 100
55 is an odd number. Odd numbers end in 1, 3, 5, 7, or 9. Even numbers end in 0, 2, 4, 6, or 8.
7 and 9 72+92 = 130
No, 34 is an even number. Even numbers end in 0, 2, 4, 6, or 8. Odd numbers end with 1, 3, 5, 7, or 9.
it goes by odd numbers, 2 + 3= 5, 5+5=10, 10 + 7=17 the rest of the pattern is 26, 37, and 50