3x + 4y = 5
To find the x-intercept, let x = 0
3(0) + 4y = 5
4y = 5
y = 5/4
The line passes through (0, 5/4), so y-intercept is 5/4.
To find x-intercept, let y = 0
3x + 4(0) = 5
3x = 5
x = 5/3
The line passes through (5/3, 0), so x-intercept is 5/3.
Plot (0, 5/4) and (5/3, 0). Draw a straight line through them.
Or,
3x + 4y = 5
3x - 3x + 4y = 5 - 3x
4y = -3x + 5
4y/4 = (-3x + 5)/4
y = (-3/4)x + 5/4
So the slope will be -3/4 and the y-intercept is 5/4; (0, 5/4)
We find the x-intercept when y = 0, so
0 = (-3/4)x + 5/4
0 - 5/4 = (-3/4)x + 5/4 - 5/4
-5/4 = (-3/4)x
(-5/4)/(-3/4) = [(-3/4)x]/(-3/4)
5/3 = x ; (5/3, 0)
Thus, the line passes through the points (0, 5/4) and (5/3, 0).
-5
It is: 3x+4y which is an algebraic expression
y = 3x 3x + 4y = 30 3x + 4(3x) = 30 3x + 12x = 30 15x = 30 x = 2 y = 3x y = 3(2) y = 6 (2, 6)
1
7(3y-2)-(-4y+9)
The lines are parallel.
(2, -1)
They are the same equation just written differently so they are both easy to graph.
-5
Sensible but hard to explain
3x+4y = 8 4y = -3x+8 y = -3/4x+2 in slope intercrpt form It has a negative slope so the straight line goes 'downhill'
2x + 3y = 17 3x + 4y = 24 (2x + 3x) + (3y + 4y) = (17 + 24) 5x + 7y = 41
3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)
Here they are in there slope intercept forms. y = -3/4x + 2 [3x+4y=8] y = -3/4x + 2 [y=-0.75x+2] Well look at that they are the same. How do you like that. So they much be equal easy to graph.
4y = 3x+11 or as y = 3/4x+11/4
x = 4 and y = 0
(-1, 5)