y = f(x) = 75x has a slope of 75 (steep) and an x,y intercept of (0,0).
Graph it as a very steep, straight line passing through the origin from lower left to upper right.
Graph that equation. If the graph pass the horizontal line test, it is an inverse equation (because the graph of an inverse function is just a symmetry graph with respect to the line y= x of a graph of a one-to-one function). If it is given f(x) and g(x) as the inverse of f(x), check if g(f(x)) = x and f(g(x)) = x. If you show that g(f(x)) = x and f(g(x)) = x, then g(x) is the inverse of f(x).
The graph of F(x), shown below, resembles the graph of G(x) = x2, but it has been changed somewhat. Which of the following could be the equation of F(x)?
What is the area bounded by the graph of the function f(x)=1-e^-x over the interval [-1, 2]?
y=x+1 there for answer is 2
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
It is 6000.
my bad its f(x) = 6000 - 75x
If 75x = 750, then (1/75)75x = (1/75)750, or x = 750/75 = 10.
75x = 33 75x/75 = 33/75 = 0.44 x = 0.44 0.44 x 100 = 44%
I am assuming the you are talking about the graph of the derivative. The graph of the derivative of F(x) is the graph such that, for any x, the value of x on the graph of the derivative of F(x) is the slope at point x in F(x).
The graph of the function f(x) = 4, is the horizontal line to the x=axis, which passes through (0, 4). The domain of f is all real numbers, and the range is 4.
Let's simplify: f(x) = 3x-3x, so f(x) =0, so y=0 The graph is a line along the x-axis.
Graph that equation. If the graph pass the horizontal line test, it is an inverse equation (because the graph of an inverse function is just a symmetry graph with respect to the line y= x of a graph of a one-to-one function). If it is given f(x) and g(x) as the inverse of f(x), check if g(f(x)) = x and f(g(x)) = x. If you show that g(f(x)) = x and f(g(x)) = x, then g(x) is the inverse of f(x).
.75 (it's simply the number being multiplied by x)
Why
Select a set of values for x. For each value calculate the value of f(x). On a graph paper, mark the points [x, f(x)].
The second graph is shifted upwards by 4 units.