answersLogoWhite

0

Restate the question: How do you graph 7x+2y=14?

The easiest way to graph this equation is to find the intercepts. . .

To find the y-intercept, let x=0: 7(0)+2y=14 <=> 2y=14 <=> 2y/2=14/2 <=> y=7, so mark the point (0,7) on the graph.

To find the x-intercept, let y=0: 7x+2(0)=14 <=> 7x=14 <=> x=2, so mark (2,0) on the graph and draw a straight line through the 2 points.

With a little practice, and if the numbers are 'nice', you can almost do this by just looking at the equation, or you can think of (0,_),(_,0). My students call this "googly eyes"!

User Avatar

Wiki User

12y ago

What else can I help you with?

Related Questions

How do I put 7x-2y equals -14 in a graph?

Manipulate such that y is the subject of the equation 7x - 2y = -14 2y = 7x +14 y = (7/2)x + 7


What is a picture put into a graph?

A picture put into a graph is a picture put into a graph


What is the y-intercept of the graph of 7x-3y21?

If you mean: 7x-3y = 21 then y = 7/3x-7 whereas -7 is the y intercept and 7/3 is the slope


The x-and y-intercepts of the graph of 7x-3y42 are?

Funtion: 7x-3y+42 =&gt; y=7/3x - 14 x-intercept: (6,0) y-intercept: (0,-14)


How do you put Graph in a sentence?

i had a graph


How do you graph y- 7x equals 49?

y - 7x = 49 can be put into slope-intercept form by adding 7x to both sides. This gives you y = 7x + 49. This means that the slope of the line is 7, and the y-intercept is 49. So, plot the point (0,49). After that, for every time x increases by 1, y increases by 7. So, plot the point (1,56). Draw a straight line between (0,49) and (1,56) and draw arrow heads on both ends of the line to indicate that it continues infinitely.


What is the slope of the graph of 7x equals 3y-8?

To find the slope of the equation (7x = 3y - 8), first rearrange it into slope-intercept form (y = mx + b). Adding 8 to both sides gives (3y = 7x + 8), and then dividing by 3 results in (y = \frac{7}{3}x + \frac{8}{3}). The slope (m) of the graph is therefore (\frac{7}{3}).


How can you tell by looking at a graph whee the solutions are in a quadratic equation?

Let's say you have the quadratic equation x2 - 7x + 12 = 0. Plot the graph of y = x2 - 7x + 12. Where y = 0 (when the graph crosses the x-axis) is a solution to the equation. In this case, it crosses at the points (3,0) &amp; (4,0) so the solutions are x = 3 and x = 4. Now if the graph never touches the x-axis, that means the solutions to the equation are complex numbers.


Is y equals -7x plus 6 parallel?

y = -7x + 6 is the equation of a straight line. It has a slope of '-7' and a y-intercept of '6'. For it to be parallel it must be compared to another line. e.g. y = -7x + 12 is a paralle line However, y = 7x + 6 is NOT a parallel line, because the slope is in a different direction.


What is the slope of the graph of 7x equals 3y minus 8?

7/3 im pretty sure Another Answer:- If: 7x = 3y-8 Then: -3y = -7x-8 And so: y = 7/3x+8/3 Therefore: the slope is 7/3 and the y intercept is 8/3


If you wanted to make the graph of y 3x plus 1 steeper which equation could you use?

y=7x+1 ( apex )


What is an example of the equation that makes the graph of y equal 6tans 7 less steep?

To make the graph of ( y = 6 \tan(7x) ) less steep, you can reduce the coefficient of the tangent function. For example, changing the equation to ( y = 3 \tan(7x) ) will make the graph less steep since the amplitude of the tangent function is halved. Alternatively, you could also decrease the coefficient of ( x ) inside the tangent, such as ( y = 6 \tan(3.5x) ), which would also reduce the steepness of the graph.