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Restate the question: How do you graph 7x+2y=14?
The easiest way to graph this equation is to find the intercepts. . .
To find the y-intercept, let x=0: 7(0)+2y=14 <=> 2y=14 <=> 2y/2=14/2 <=> y=7, so mark the point (0,7) on the graph.
To find the x-intercept, let y=0: 7x+2(0)=14 <=> 7x=14 <=> x=2, so mark (2,0) on the graph and draw a straight line through the 2 points.
With a little practice, and if the numbers are 'nice', you can almost do this by just looking at the equation, or you can think of (0,_),(_,0). My students call this "googly eyes"!
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The x-and y-intercepts of the graph of 7x-3y42 are?
Funtion: 7x-3y+42 => y=7/3x - 14 x-intercept: (6,0) y-intercept: (0,-14)
How can you tell by looking at a graph whee the solutions are in a quadratic equation?
Let's say you have the quadratic equation x2 - 7x + 12 = 0. Plot the graph of y = x2 - 7x + 12. Where y = 0 (when the graph crosses the x-axis) is a solution to the equation. In this case, it crosses at the points (3,0) & (4,0) so the solutions are x = 3 and x = 4. Now if the graph never touches the x-axis, that means the solutions to the equation are complex numbers.
If you wanted to make the graph of y 3x plus 1 steeper which equation could you use?
y=7x+1 ( apex )
7x - 4 7x plus 4?
(7x - 4)(7x + 4).
How do you solve -7x plus 6 plus 7x-2?
-7x + 6 + 7x - 2 = 4
