Restate the question: How do you graph 7x+2y=14?
The easiest way to graph this equation is to find the intercepts. . .
To find the y-intercept, let x=0: 7(0)+2y=14 <=> 2y=14 <=> 2y/2=14/2 <=> y=7, so mark the point (0,7) on the graph.
To find the x-intercept, let y=0: 7x+2(0)=14 <=> 7x=14 <=> x=2, so mark (2,0) on the graph and draw a straight line through the 2 points.
With a little practice, and if the numbers are 'nice', you can almost do this by just looking at the equation, or you can think of (0,_),(_,0). My students call this "googly eyes"!
Funtion: 7x-3y+42 => y=7/3x - 14 x-intercept: (6,0) y-intercept: (0,-14)
Let's say you have the quadratic equation x2 - 7x + 12 = 0. Plot the graph of y = x2 - 7x + 12. Where y = 0 (when the graph crosses the x-axis) is a solution to the equation. In this case, it crosses at the points (3,0) & (4,0) so the solutions are x = 3 and x = 4. Now if the graph never touches the x-axis, that means the solutions to the equation are complex numbers.
y=7x+1 ( apex )
(7x - 4)(7x + 4).
-7x + 6 + 7x - 2 = 4
Manipulate such that y is the subject of the equation 7x - 2y = -14 2y = 7x +14 y = (7/2)x + 7
A picture put into a graph is a picture put into a graph
If you mean: 7x-3y = 21 then y = 7/3x-7 whereas -7 is the y intercept and 7/3 is the slope
Funtion: 7x-3y+42 => y=7/3x - 14 x-intercept: (6,0) y-intercept: (0,-14)
i had a graph
Let's say you have the quadratic equation x2 - 7x + 12 = 0. Plot the graph of y = x2 - 7x + 12. Where y = 0 (when the graph crosses the x-axis) is a solution to the equation. In this case, it crosses at the points (3,0) & (4,0) so the solutions are x = 3 and x = 4. Now if the graph never touches the x-axis, that means the solutions to the equation are complex numbers.
y - 7x = 49 can be put into slope-intercept form by adding 7x to both sides. This gives you y = 7x + 49. This means that the slope of the line is 7, and the y-intercept is 49. So, plot the point (0,49). After that, for every time x increases by 1, y increases by 7. So, plot the point (1,56). Draw a straight line between (0,49) and (1,56) and draw arrow heads on both ends of the line to indicate that it continues infinitely.
y = -7x + 6 is the equation of a straight line. It has a slope of '-7' and a y-intercept of '6'. For it to be parallel it must be compared to another line. e.g. y = -7x + 12 is a paralle line However, y = 7x + 6 is NOT a parallel line, because the slope is in a different direction.
7/3 im pretty sure Another Answer:- If: 7x = 3y-8 Then: -3y = -7x-8 And so: y = 7/3x+8/3 Therefore: the slope is 7/3 and the y intercept is 8/3
y=7x+1 ( apex )
you draw a circle and then put it on a graph
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