Well, honey, when you simplify 3t + 6t, you just add those coefficients together like you're mixing a cocktail - 3 + 6 gives you 9. Then you just slap that sum in front of the variable t, so your final answer is 9t. Easy peasy lemon squeezy!
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2r + 7r - 6t - r + 7t = 8r + t
6t - 5t - 6 = (3t + 2)(2t - 3)
6t - 4x
8t^2 - 11t - 4
3t + 7 = 2t - 5 3t = 2t - 12 t = -12
4
2r + 7r - 6t - r + 7t = 8r + t
6t2+17t+7 = (3t+7)(2t+1) when factored
3
3t
6t2+25+11 = (3t+11)(2t+1) when factored Use the quadratic equation formula.
5r x 6t = 30rt
Let's break it down, friend. First, we solve the equation 3t - 7 = 5. Add 7 to both sides to isolate 3t, giving us 3t = 12. Now, to find t, we divide both sides by 3, so t = 4. Lastly, if 6t equals something, you can substitute t with 4 to find the value of 6t.
That's a simple example of system of equations. There are quite a number of methods for solving those, but the easiest here would be to calculate one variable from first equation and substitute it into second. 2s + 3t = 28 5s + 6t = 61 Let's calculate s from the first equation: 2s + 3t = 28, 2s = 28 - 3t s = 14 - 3t/2 Substitute s into second equation 5s + 6t = 61, 5(14 - 3t/2) + 6t = 61, 70 - 15t/2 + 6t = 61, 70 - 3t/2 = 61, 3t/2 = 9, t = 6. We can then substitute t back into first equation: 2s + 3t = 28, 2s + 3 * 6 = 28, 2s = 10, s = 5. So the final answer is: s = 5 t = 6
If that's + 7t, the answer is (3t + 5)(2t - 1) If that's - 7t, the answer is (3t - 5)(2t + 1)
6t+t = 7t
6t - 5t - 6 = (3t + 2)(2t - 3)