Ok so your equation reads like this (I assume you forgot the +):
3 - 4x = 10x +10
The goal is to get the x's on one side and the other numbers on the other. It doesnt matter which side has which, so I will move the numbers to the right and the x's to the left. So first subtract 3 from both sides:
3 - 3 - 4x = 10x + 10 - 3
-4x = 10x + 7
Now subtract 10x from both sides.
-4x - 10x = 10x - 10x + 7
-14x = 7
Now that we have like terms on both sides, all you need to do is divide both sides by -14 to solve for x.
-14x / -14 = 7 / -14
x = -1 / 2
If: 10X = 2.7 then X = 2.7/10 => 0.27
x=-8
-10x = -50 Divide both sides by -10 remembering that a minus divided by a minus the quotient then becomes positive: x = 5 So: -10*5 = -50
10x=80 divide each side by 10 to get x by itself 10/10x=1x 80/10=8 x=8
-8 + 10x = 18 10x = 18+8 10x = 26 x = 26/10 x = 2.6
If: 10X = 2.7 then X = 2.7/10 => 0.27
10x+7=(-3) 10x=(-10) x=(-1)ans
x=-8
Divide each side of the equation by 10 .
10x - 3 = 17 Add 3 to both sides: 10x = 20 Divide both sides by 10: x = 2
2x+8x-2=22 10x-2=22 10x+2=+2 10x=24 10/10=24/10 x=2.4
-10x = -50 Divide both sides by -10 remembering that a minus divided by a minus the quotient then becomes positive: x = 5 So: -10*5 = -50
8 = 10x/(10 + x) Multiply both sides by (10 + x) to give: 8*(10+x) = 10x Simplify: 80 + 8x = 10x Subtract 8x from both sides: 80 = 2x Divide both sides by 2: 40 = x
To solve this, you would normally set up a systems of equations 10x + 2y = 10 10x + 2y = 11 However, it clearly makes no sense and has no answer. To prove this mathematically, subtact the two equations. 10x - 10x = 0 2y - 2y = 0 10-11 = -1 Therefore, it is basically saying that 0 + 0 = -1 Obviously, that is incorrect, so this question has no solutions.
1) 5x2-55=90 +55 +55 2) 10x=145 /10 /10 x=14.5
The derivative of 10x is 10. This is irrespective of the value of x.
10x-1=35 is equal to 10x-1+1=35+1, or 10x=36 10x=36 is equal to 10x/10=36/10, or x=3.6