Well, isn't that a happy little math problem we have here? To solve 9 to the power of x equals 243, we can rewrite 243 as 3 to the power of 5. Since 9 is 3 squared, we can rewrite 9 as 3 to the power of 2. Now we have 3 to the power of 2x equals 3 to the power of 5. So, setting the exponents equal to each other, we get 2x equals 5. Therefore, x equals 5 divided by 2, which simplifies to x equals 2.5. Happy solving!
D - 9 = 9 d = 9 + 9 d = 18
x= -8
10 to the power of 9 equals 1,000 million.
x=2 because 9-(14)=-5
3 3^5 = 243 (3 x 3) x (3 x 3) x 3 = 243 9 x 9 x 3 = 243 81 x 3 = 243
9 x 27 equals 243
9 times 27 equals 243.
9 times 27 = 243
To determine how many times 9 goes into 243, we can divide 243 by 9. The result is 27, which means that 9 goes into 243 27 times. This is because 9 multiplied by 27 equals 243.
z4-9=0 z4=9
27 goes into 243 a total of 9 times. This can be calculated by dividing 243 by 27, which equals 9.
27 x 9 equals 243. This multiplication can be solved by multiplying 27 by 9, which is equivalent to adding 27 to itself 9 times. Another way to solve this is by recognizing that 27 is 3 times 9, so multiplying 27 by 9 is the same as multiplying 3 by 9 and then multiplying the result by 10, which gives us 243.
27 multiplied by 9 equals 243.
Actually, (3) raised to the (5)th power equals (243) because (3^5) is calculated as (3 \times 3 \times 3 \times 3 \times 3), which equals (243). To break it down, (3^2 = 9), (3^3 = 27), (3^4 = 81), and finally (3^5 = 243). Thus, (3^5 = 243) is correct.
The following equal 243: 27 x 9 81 x 3
1 x 243, 3 x 81, 9 x 27.
The power produced by the circuit can be calculated using the formula P = I * V, where P is power, I is current, and V is voltage. In this case, P = 9 amps * 27 volts = 243 watts. So, the circuit would produce 243 watts of power.