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Q: How do you solve an exponential equation?

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For an exponential function: General equation of exponential decay is A(t)=A0e^-at The definition of a half-life is A(t)/A0=0.5, therefore: 0.5 = e^-at ln(0.5)=-at t= -ln(0.5)/a For exponential growth: A(t)=A0e^at Find out an expression to relate A(t) and A0 and you solve as above

Log=ea 47.38

Basically, in an exponential expression (or equation) you have the independent variable in the exponent. For example: 5 times 10x The general form of an exponential function can be written as: abx or: aekx where a, b, and k are constants, and e is approximately 2.718. Note that just having a power doesn't mean you have an exponential equation. For example, in x3 the variable does NOT appear in the exponent, so it is not an exponential expression.

The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)The given equation is exponential, not logarithmic!The logarithmic equation equivalent to ea= 47.38 isa = ln(47.38)ora = log(47.38)/log(e)

ln 60 = a

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depends on the question but an EXPONENTIAL EQUATION is in the for 2^x = 4 and you have to solve for x.

Logarithmic equation

For an exponential function: General equation of exponential decay is A(t)=A0e^-at The definition of a half-life is A(t)/A0=0.5, therefore: 0.5 = e^-at ln(0.5)=-at t= -ln(0.5)/a For exponential growth: A(t)=A0e^at Find out an expression to relate A(t) and A0 and you solve as above

Do you mean "equations involving exponential functions"? Yes,

10a = 478

Log=ea 47.38

you don't answer an equation, you solve an equation

Log 200=a can be converted to an exponential equation if we know the base of the log. Let's assume it is 10 and you can change the answer accordingly if it is something else. 10^a=200 would be the exponential equation. For a base b, we would have b^a=200

Sure. You can always 'solve for' a variable, and if it happens to be the only variable in the equation, than that's how you solve the equation.

a quadratic equation must be in this form ax^2+bx+c=0 (can either be + or -) an exponential just means that the function grows at an exponential rate f(x)=x^2 or x^3

That completely depends on exactly what operation you have in mind. You can "do" several different types of operations to an equation, such as solve it, differentiate it, rearrange it, factor it, or apply the same arithmetic procedure to both sides of it. But you can't "do" the equation.

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