If an infinite surd is like (√(6+√(6+√(6+√(6...),to solve it, follow these steps:
Set x = √(6+√(6+√(6+√(6...
therefore x2 = 6+√(6+√(6+√(6+√(6...
therefore x2 = 6+x
therefore 6+x-x2 = 0.
Factorising the expression gives you (-x+3)(x+2)=0
Only the positive answer need be concerned with:
-x+3=0
therefore -x = -3
therefore x = 3.
Infinite surd is a term used in mathematics. The definition of an infinite surd is a never ending irrational number with an exact value that would be left in square root form.
No.
Surds are irrational square root numbers that cannot be solved but they can be simplified. For example the square root of 12 can be simplified to 2 times the square root of 3.
A surd in the form a√b cannot, in general, be simplified.
Normally they are.
Infinite surd is a term used in mathematics. The definition of an infinite surd is a never ending irrational number with an exact value that would be left in square root form.
2
the same way you find chuck Norris
Yes it is a surd
If the value of the surd is positive, then it will be another surd. Otherwise it will be a complex number.
A surd is the square root of an integer (whole number), e.g. square root of 2 is a surd. Pi is not the square root of an integer so not a surd, just an irrational number
I am pretty sure that the cube root of negative seven is a surd. I checked on the calculator.......and it showed a negative number.....??I think when it is not a surd...it's supposed to say error, so the number probably means that it is a surd..
No. It is not a criminal or civil offence!
27
No.
i did
Surds are irrational square root numbers that cannot be solved but they can be simplified. For example the square root of 12 can be simplified to 2 times the square root of 3.